Data Communications and Computer Networks Chapter 4 CS 3830 Lecture 19 Omar Meqdadi Department of Computer Science and Software Engineering University.

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Data Communications and Computer Networks Chapter 4 CS 3830 Lecture 19 Omar Meqdadi Department of Computer Science and Software Engineering University of Wisconsin-Platteville

Network Layer4-2 Chapter 4: Network Layer  4. 1 Introduction  4.2 Virtual circuit and datagram networks  4.4 IP: Internet Protocol  Datagram format  IPv4 addressing  IPv6  4.5 Routing algorithms  Link state  Distance Vector  Hierarchical routing  4.6 Routing in the Internet  RIP  OSPF  BGP  4.7 Broadcast and multicast routing

Network Layer4-3 The Internet Network layer forwarding table Host, router network layer functions: Routing protocols path selection RIP, OSPF, BGP IP protocol addressing conventions datagram format packet handling conventions Transport layer: TCP, UDP Link layer physical layer Network layer

Network Layer4-4 Chapter 4: Network Layer  4. 1 Introduction  4.2 Virtual circuit and datagram networks  4.4 IP: Internet Protocol  Datagram format  IPv4 addressing  IPv6  4.5 Routing algorithms  Link state  Distance Vector  Hierarchical routing  4.6 Routing in the Internet  RIP  OSPF  BGP  4.7 Broadcast and multicast routing

Network Layer4-5 IP datagram format ver length 32 bits data (variable length, typically a TCP or UDP segment) 16-bit identifier header checksum time to live 32 bit source IP address IP protocol version number header length (bytes) max number remaining hops (decremented at each router) for fragmentation/ reassembly total datagram length (bytes) upper layer protocol to deliver payload to head. len type of service “type” of data flgs fragment offset upper layer 32 bit destination IP address Options (if any) E.g. timestamp, record route taken, specify list of routers to visit. how much overhead with TCP? r 20 bytes of TCP r 20 bytes of IP r = 40 bytes + app layer overhead

Network Layer4-6 IP Fragmentation & Reassembly  network links have MTU (max.transfer size) - largest possible link-level frame.  different link types, different MTUs  large IP datagram divided (“fragmented”) within net  one datagram becomes several datagrams  “reassembled” only at final destination  IP header bits used to identify, order related fragments fragmentation: in: one large datagram out: 3 smaller datagrams reassembly

Network Layer4-7 IP Fragmentation and Reassembly ID =x offset =0 fragflag =0 length =4000 ID =x offset =0 fragflag =1 length =1500 ID =x offset =185 fragflag =1 length =1500 ID =x offset =370 fragflag =0 length =1040 One large datagram becomes several smaller datagrams Example r 4000 byte datagram r MTU = 1500 bytes 1480 bytes in data field offset = 1480/8

Network Layer4-8 Chapter 4: Network Layer  4. 1 Introduction  4.2 Virtual circuit and datagram networks  4.4 IP: Internet Protocol  Datagram format  IPv4 addressing  IPv6  4.5 Routing algorithms  Link state  Distance Vector  Hierarchical routing  4.6 Routing in the Internet  RIP  OSPF  BGP  4.7 Broadcast and multicast routing

Network Layer4-9 IP Addressing: introduction  IP address: 32-bit identifier for host, router interface  interface: connection between host/router and physical link  router’s typically have multiple interfaces  host typically has one interface  IP addresses associated with each interface =

Network Layer4-10 Subnets  IP address:  subnet part (high order bits)  host part (low order bits)  What’s a subnet ?  device interfaces with same subnet part of IP address  can physically reach each other without intervening router network consisting of 3 subnets subnet

Network Layer4-11 Subnets / / /24 Recipe  To determine the subnets, detach each interface from its host or router, creating islands of isolated networks.  Each isolated network is called a subnet. Subnet mask: /24

Network Layer4-12 Subnets How many?

Network Layer4-13 IP addressing: CIDR CIDR: Classless InterDomain Routing  subnet portion of address of arbitrary length  address format: a.b.c.d/x, where x is # bits in subnet portion of address subnet part host part /23

Network Layer4-14 IP addressing: the last word... Q: How does an ISP get block of addresses? A: ICANN: Internet Corporation for Assigned Names and Numbers  allocates addresses  manages DNS  assigns domain names, resolves disputes  !! Problem !!  There are no more 32-bit IP addresses left  What can we do?

Network Layer4-15 NAT: Network Address Translation local network (e.g., home network) /24 rest of Internet Datagrams with source or destination in this network have /24 address for source, destination (as usual) All datagrams leaving local network have same single source NAT IP address: , different source port numbers

Network Layer4-16 NAT: Network Address Translation  Motivation: local network uses just one IP address as far as outside world is concerned:  range of addresses not needed from ISP: just one IP address for all devices  can change addresses of devices in local network without notifying outside world  can change ISP without changing addresses of devices in local network  devices inside local net not explicitly addressable, visible by outside world (a security plus).

Network Layer4-17 NAT: Network Address Translation  16-bit port-number field:  60,000 simultaneous connections with a single LAN-side address!  NAT is controversial:  routers should only process up to layer 3  violates end-to-end argument NAT possibility must be taken into account by app designers, eg, P2P applications  address shortage should instead be solved by IPv6

Network Layer4-18 NAT: Network Address Translation Implementation: NAT router must:  outgoing datagrams: replace (source IP address, port #) of every outgoing datagram to (NAT IP address, new port #)... remote clients/servers will respond using (NAT IP address, new port #) as destination addr.  remember (in NAT translation table) every (source IP address, port #) to (NAT IP address, new port #) translation pair  incoming datagrams: replace (NAT IP address, new port #) in dest fields of every incoming datagram with corresponding (source IP address, port #) stored in NAT table

Network Layer4-19 NAT: Network Address Translation S: , 3345 D: , : host sends datagram to , 80 NAT translation table WAN side addr LAN side addr , , 3345 …… S: , 80 D: , S: , 5001 D: , : NAT router changes datagram source addr from , 3345 to , 5001, updates table S: , 80 D: , : Reply arrives dest. address: , : NAT router changes datagram dest addr from , 5001 to , 3345