Momentum and Impulse Momentum Momentum can be defined as "mass in motion." All objects have mass; so if an object is moving, then it has momentum Momentum.

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Presentation transcript:

Momentum and Impulse

Momentum Momentum can be defined as "mass in motion." All objects have mass; so if an object is moving, then it has momentum Momentum depends upon the variables mass and velocity massvelocity Momentum = mass * velocity p = m * v where m = mass and v=velocity

Momentum is a vector quantity To fully describe the momentum of a 5-kg bowling ball moving westward at 2 m/s, you must include information about both the magnitude and the direction of the bowling ball p = m * v p = 5 kg * 2 m/s west p = 10 kg * m / s west

Elastic and inelastic Collisions When a Ball hits the ground and sticks, the collision would be totally inelastic When a Ball hits the ground and bounces to the same height, the collision is elastic All other collisions are partially elastic collision

Check Your Understanding Determine the momentum of a kg halfback moving eastward at 9 m/s. –p = mv = 60 kg ( 9 m/s ) – 540 kg *m /s east 1000-kg car moving northward at 20 m/s. –p = mv = 1000 kg ( 20 m/s ) –20,000 kg *m /s north Given: m = 60Kg v= 9 m/s Find : momentum (p) Given: m = 1000Kg v= 20 m/s

Momentum and Impulse Connection To stop such an object, it is necessary to apply a force against its motion for a given period of time force Impulse = Change in momentum J = F (t) = m  v

Check Your Understanding If the halfback experienced a force of 800 N for 0.9 seconds to the north, determine the impulse J = F ( t ) = m  v 800N ( 0.9s ) = 720 N*s the impulse was 720 N*s or a momentum change of 720 kg*m/s Given: F = 800 N t = 0.9 s Find : Impulse (J)

Impulse Question #2 A 0.10 Kg model rocket’s engine is designed to deliver an impulse of 6.0 N*s. If the rocket engine burns for 0.75 s, what is the average force does the engine produce? J = F ( t ) = m D v 6.0 N*s = F ( 0.75s ) 6.0 N*s/ 0.75s = F 8.0 N = F Given: F = 800 N t = 0.9 s Find : Average Force

Impulse Question # 3 A Bullet traveling at 500 m/s is brought to rest by an impulse of 50 N*s. What is the mass of the bullet? J = F ( t ) = m  v 50 N*s = m ( 500 m/s – 0 m/s ) 50 kg-m/s 2 *s / 500 m/s = m.1 kg = m Given: v = 500 m/s J = 50 N*s Find : m = ?

Summary the impulse experienced by an object is the force*time the momentum change of an object is the mass*velocity change the impulse equals the momentum change