2a – 7 = 3a + 10 Vertical <‘s are ≅

How do you find the center of this circle? The center of a circle is the midpoint of any diameter.

Definition of Linear pair– 2 angles that are adjacent and supplementary 2x x – 84 = 180

Definition of perp. lines - 2 lines that intersect to form a right angle Definition of complementary <‘s - 2 angles whose sum = 90 degrees

AB is on a number line. Explain how to find its midpoint. A + B 2 A _____ has no size, no dimensions, just position. Point

Write the standard equation of a circle. (x – h ) ² + (y – k )² = r² Simplify √ 175 5√7

Solve for x. Explain your answer. 3x + 20 = 8x – 5 vertical angles are congruent

__________ is the set of all points. Space 4 _____ points determine space. noncoplanar

The midpoint of GD is (4,-5) and the coordinates of D are (-3,1). Find the coordinates of G. ___________________________________ G MD (4, -5)(-3,1) Double the midpoint and do the opposite of the given endpoint. Step 1 --(8,-10) Step 2---(+3,-1) Answer (11,-11)

What is the easiest way to prove a quad is a parallelogram? If the midpoints of the diagonals are the same.

What postulate is demonstrated here? The intersection of 2 planes is a line.

(2,5);(7,5);(-4,5) Points on the same line because all the y-coordinates are the same. y = 5 Horizontal line

(3,2), ( 3, -1), (3, 7) Points on the same line because all the x’s are the same Vertical line X=3

What is a conjecture? A conclusion you reach using inductive reasoning.

1.Write the Circle Equation X ² + y² = 4 Center (0,0) Radius = 2

Are the following points collinear, coplanar, or noncoplanar? (Why?) H, G, C Coplanar Any 3 pts lie in a plane F,B,E,A Coplanar – ll lines

D,C,E,H Noncoplanar Skew lines Are the following points collinear, coplanar, or noncoplanar? (Why?)

Points that are in space are ___________points. Noncoplanar

If a circle has a center (4,-5) and it is tangent to the y- axis, what would its equation look like? (X-4) ² + (y+5)²= 16 Radius = 4 (distance from y-axis)

Write the equation of a circle for a circle with an area = 121 π and a center ( -10, 4). (X+10) ² + (y-4)² = π = πr² 121 = r²

MP = =24 MR = RP = 12 Def of midpt. Coordinate of R = -2 – 12 = 14 or = -14

(-2,7) (-2,-3) Find the center of the above circle- which is the midpt. of the diameter. (-2,2) Find the radius of the above circle. r = 5

Write an equation. 7X = 35 X = 5 Name the postulate you used to write the above equation. Segment Addition Postulate Find the coordinate of E = -4

Find the midpoint of AB if you are on a number line. A+B 2 If you are in a plane. x ₁ + x ₂, y ₁ + y ₂ 2 2 ( )