Reactor Design. الأول : إيه ياعم مالك عمال تتنطط كدة من بنش لبنش وفرحان قوي ، نجحنا وللا إيه؟ الثاني : نجحنا إيه هو احنا لسة امتحنا أصلا ، أنا أصلي فرحان.

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Presentation transcript:

Reactor Design

الأول : إيه ياعم مالك عمال تتنطط كدة من بنش لبنش وفرحان قوي ، نجحنا وللا إيه؟ الثاني : نجحنا إيه هو احنا لسة امتحنا أصلا ، أنا أصلي فرحان إن النهاردة آخر سكشن في المادة دي الأول : ومين بقى اللي ضحك عليك وقالك كدة؟ ده احنا أصلا عندنا سكاشن اضافي طرااااااااااااخ الثاني : آآآآآه... كدة تقول لي خبر زي ده توقعني من فوق البنش  هو احنا مش خلصنا ال vessel المرة اللي فاتت؟ والمرة دي عندنا non- isothermal ودي آخر حاجة أخدناها؟ الأول : ياااااااااه ده إنت قديم قوي ، فيه يا فالح جزء ال catalysis بتاع د / الأهواني لسة فيه سكاشن الثاني : catalysis ؟د / الأهواني؟ يا أخي المادة دي عاملة زي مسلسل ليالي الحلمية كل ما نقول خلاص ده آخر جزء نلاقي جزء جديد بأبطال مختلفين !!!!!

Finally

WHAT IS THE DIFFERENCE BETWEEN THE DESIGN STRATEGY OF ISOTHERMAL AND NON-ISOTHERMAL REACTORS?

 Isothermal Reactor Design: All what we need is the material balance equation in addition to the rate equation.  Non-isothermal Reactor Design: Beside the above information we need the energy balance equation.

WHY WE NEED THE ENERGY BALANCE?

Energy Balance Equation

NON-ISOTHERMAL REACTORS DESIGN EQUATIONS

CSTR R(Y) Removal of Heat G(Y) Generation of Heat

PFR

Batch

MULTIPLE STEADY STATES IN CSTR

R(T) T Increasing T 0 Variation of heat removal line with inlet temperature:

Finding Multiple Steady States with T 0 varied: 15

Stability of multiple state temperatures 16

IGNITION-EXTINCTION CURVE

18

Temperature ignition-extinction curve 19

SHEET 7 Sheet 1, Sheet 2…Sheet 7!!! When will the slide of “The End” come?!!!  Sheet 1, Sheet 2…Sheet 7!!! When will the slide of “The End” come?!!! 

1.A first order gas phase irreversible exothermic reaction takes place in an adiabatic tubular PFR. The reaction rate constant is:k = * e /RT sec -1 and E is in cal/mole The velocity of flow v = 10 cm/sec, the heat of reaction is (-ΔH) = cal/mole, the density of the fluid is gm/cm 3 and the specific heat of gases Cp = 1.2 cal/gm. k. Feed temperature is 80ºC and feed concentration C A = 0.01 gmole/lit. What is the length of the reactor necessary to achieve 90% conversion and what is the exit temperature?

2.A reaction is being carried out in a CSTR of volume 10 m 3 ; the feed solution contains a reagent of concentration 5 kmole/m 3 and is supplied at a rate of m 3 /sec. The reagent decomposes irreversibly according to a first order reaction, liberating 2 x 10 7 joule of heat per kmole reacting. The velocity constant is given by k = e /T sec -1, and the solution density equals 850 kg/m 3, solution heat capacity equals 2200 joule/kg. k. If the feed solution is provided at 290 k, calculate: The reaction temperature. The extent of reaction.