 Pages Review Homework

page 192 #25 Let x = an integer Let x+1 = 1 st consecutive integer x+(x+1)=45 2x=44 x=22 x+1=23 22, =45 45=45 

Page 192 # 26 Let x= even integer Let x+2=1 st consecutive even integer Let x+4=2 nd consecutive even integer x+(x+2)+(x+4)=72 3x+6=72 3x=66 x=22 22,24, =72 72=72 

Page ) -45, ) 11, 13, 15, 17 29) 20, 22 30) 24, 25, 26 31) 3 32) -7 33) 10, 40 34) 25, 55 35) 4.5 inches x 7.5 inches 36) 20, 80, 80 37) 15, 17, 19 38) 0

Integer worksheet practice

Same Direction Travel page 176 If two people or objects are travelling in the same direction to the same place, the distance they each travel will be the same. If you determine the distance they travel (distance equals speed (rate) times time d=st) you can set them equal to each other and solve for the unknowns.

Example Same Direction Travel page 176 SpeedTimeDistance Train 145t45t Train 260t-160(t-1) We solve the problem and get t=4. Now we go back to the word problem. “When will the second train catch up to the first train. 4 hours is the time the 1 st train travels. so 3 hours is the time the 2 nd train travels. The 1 st train left at 4pm, so the 2 nd train left at 5pm. 4+4 or 5+3 = 8PM

Practice page 177 Soyoon is moving to a new home. A moving van leaves Soyoon’s house travelling at an average rate of speed of 40 km/h. Soyoon ‘s family leaves the house 30 minutes later following the same route (path) in their car. The car travels at an average rate of speed of 60 km/h. When will the car catch up to the van? SpeedTimeDistance Moving Van40 km/hx40(x) Car60 km/hx-0.560(x-0.5)

40x = 60(x- 0.5) 40x = 60x x = -30 x = 1.5 hours 1.5 hours is the time for the moving van. The car will catch the van in = 1 hour. SpeedTimeDistance Moving Van40 km/hx40(x) Car60 km/hx-0.560(x-0.5) SpeedTimeDistance Moving Van40 km/hx+0.540(x+0.5) Car60 km/hx60x 40(x+0.5)=60x 40x+20=60x 20x=20 x=1 After the car has travelled for 1 hour

Practice / Homework Page 184 #1 page 185 – 186 # 4-9