Transfer of ions examples: water treatments and water purification starting from soluble ionic salts, just a simple rearrangement of ions the driving.

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Transfer of ions examples: water treatments and water purification starting from soluble ionic salts, just a simple rearrangement of ions the driving force for the reaction, is the formation of a (s), (l),or (g) evidence for chemical reactivity is observed if: a solid precipitate is seen forming the (l) symbol for a molecule is written into the balance equation as in the case for a acid-base neutralization reaction gaseous bubbles are produced in the reaction mixture

(aq) Cu(NO 3 ) 2 (aq) Na 2 SO 4 (aq) CuCl 2 (aq) H 2 SO 4 (aq) Cu(NO 3 ) 2 (aq) Ag 2 SO 4 (s) Cu(CO 3 ) 2 (s) Na 2 SO 4 (aq) NaCl (aq) HNO 3 (aq) NaNO 3 (aq) AgNO 3(aq) Na 2 CO 3 (aq) Cu(NO 3 ) 2 (aq) HNO 3 (aq) AgCl (s) H 2 CO 3 = CO 2 + H 2 O NaCl (aq) Ag 2 CO 3 (s) NaNO 3 (aq) Cu 2+ SO 4 2- Na + NO 3 - H+H+ Cl - Ag + NO 3 - 2Na + CO 3 2- Cu 2+ SO 4 2- Na + NO 3 - H+H+ Cl - Ag + NO 3 - 2Na + CO Write correct ions and ionic salt formulas 2.Apply solubility rules to determine if salts are Soluble (aq) or insoluble (s) in water

Solubility Rules for Ionic Salts in H 2 O Thus All ionic salts of group I ions, –Li +, Na +, K + are solubule in water All ionic salts of nitrate ion, –NO 3 _ are solubule in water All ionic salts of ammonium ion, –NH 4 + are solubule in water K+K+ Cl – K+K+ This solubility separation is called solvation-dissociation NaCl dissolves Water wedges in between

Acids often have H listed first in their chemical formula Strong Acids (strong electrolytes) H + ClO 4 - (aq) 2H + SO 4 2- (aq) H + Cl - (aq) H + NO 3 - (aq) (l) Weak Acids Weak Electrolytes Stay as liquids Stay molecular

1.Write correct ion and ionic salt formulas 2.Apply solubility rules to determine if salts are Soluble (aq) or insoluble (s) in water silver (I) nitrate + sodium chloride silver (I) chloride + sodium nitrate Ag + (NO 3 ) – Na + Cl - Ag + (NO 3 ) – Na + Cl - Ag NO 3 Na ClAg ClNa NO 3 (aq) (s)(aq)

1.Write correct ion and ionic salt formulas 2.Apply solubility rules to determine if salts are Soluble (aq) or insoluble (s) in water soduim phosphate + barium chloride barium phosphate + sodium chloride Na + (PO 4 ) 3- Ba 2+ Cl - Ba 2+ Cl - Na + (PO 4 ) 3- Na 3 PO 4 BaCl 2 Ba 3 (PO 4 ) 2 NaCl (aq) (s)(aq)

Transfer of electrons examples: batteries, corrosion, metabolism starting from an ionic salt and an element, an element and salt are produced. the driving force for the reaction is the transfer of electrons which may result in the formation of a (s), (l),or (g) evidence for chemical reactivity is observed if: a solid precipitate is seen forming the (l) symbol for a molecule is written into the balance equation as in the case for a acid-base neutralization reaction gaseous bubbles are produced in the reaction mixture

1.Write correct ion and ionic salt formulas 2.Apply solubility rules to determine if salts are Soluble (aq) or insoluble (s) in water hydrochloric acid + magnesium metal hydrogen gas + magnesium chloride H+H+ Cl - Mg Cl - Mg 2+ H2H2 HClMgH2H2 MgCl 2 (aq)(s)(g)(aq)

1.Write correct ion and ionic salt formulas 2.Apply solubility rules to determine if salts are Soluble (aq) or insoluble (s) in water hydrochloric acid + copper metal silver metal + sodium nitrate Ag + NO 3 - Cu NO 3 - Cu 2+ Ag AgNO 3 CuAgCu(NO 3 ) 2 (aq)(s) (aq)

What reactant was oxidized? (s) magnesium metal solid (g) oxygen gas (s) magnesium oxide solid ionic salt What reactant was reduced? Mg O O2OO2O Mg 2+ O 2– Mg o lost electrons Oxygen gained electrons

What reactant was oxidized? 432 (s) iron metal solid (g) oxygen gas (s) iron (III) oxide solid TM ionic salt What reactant was reduced? Fe 3+ O 2– Fe 3+ O 2– Fe O Iron metal lost electrons O2OO2O Oxygen gained electrons

Fe o Fe e - Oxidation OIL Cl 2 o + 2e - 2Cl – Reduction RIG Fe (s) + Cl 2 (g) FeCl 2 (s) 111 Combination - Synthesis (the REDOX process defined) Analyzing the half reactions Fe 2+ Cl – iron (II) chloridechlorine gasiron metalforms combining both half reactions 1 Fe (s) + 1 Cl 2 (g) 1 FeCl 2 (s) the electrons on the reactant side cancel the electrons on the product side