Initial momentum of entire system is zero (neither object has KE – neither is moving)

Slides:



Advertisements
Similar presentations
Newton's Third Law of Motion. Third Law - to every action force, there is an equal and opposite reaction *when you jump on a trampoline, you exert a downward.
Advertisements

Interactions A force is one side of an interaction. When two objects interact, they exert forces on each other. A B Newton’s third law says that these.
Chapter 7 Newton’s 3rd Law of Motion
Bouncing Impulse and The conservation of Momentum.
Newton’s 3 rd Law and Momentum. Newton’s 3 rd Law When one object exerts a force on a second object, the second object exerts a force on the first that.
Newton’s 3 rd Law of Motion Ch 3 Sect 3. 3 rd Law To every action force there is an equal and opposite reaction force To every action force there is an.
Last time, we examined how an external impulse changes the momentum of an object. Now, we will look at how multiple objects interact in a closed system.
Momentum, Impulse and Law of Conservation of Momentum Starter Questions.
Two equal-mass particles (A and B) are located at some distance from each other. Particle A is held stationary while B is moved away at speed v. What happens.
Motion & Forces Action and Reaction  Newton’s Third Law  Momentum  Conservation of Momentum.
Take out tables. On a separate sheet: Make a list of every equation we’ve already used in this class that has the velocity term in it.
WELCOME! THE TOPIC FOR TODAY IS…. Newton’s 2 nd & 3 rd Laws Test Review Cannons & Cannonball s Net ForceAction / Reaction Yes/ NoMath
Notes Chapter 8 Momentum Objectives:
Conservation of Momentum Momentum before interaction = Momentum after interaction.
Linear Momentum & Impulse
Conservation of Momentum (in 1D) SPH4U. Newton’s 3 rd Law The force B exerts on A The force A exerts on B.
Conservation of Energy and Momentum Physics 6(D).
Newton’s Third Law of Motion
Impulse Momentum 1 Conservation. Impulse Momentum 2 The simplicity of momentum The astronaut has greater mass and slower velocity The wrench has less.
Conservation of Momentum Momentum before interaction = Momentum after interaction.
Chapter 6.3 Learning Goals
Physics 11 Mr. Jean May 8 th, The plan: Video clip of the day Thursday –Rocket Build Day Recoil 1-D collisions.
6.3 Newton’s Third Law Newton’s Third Law (action- reaction) applies when a force is placed on any object, such as a basketball.
LAW OF CONSERVATION OF MOMENTUM
Forces & Newton’s Laws Ch. 4. Forces What is a force? –Push or pull one body exerts on another –Units = Newton (N) –Examples: List all of the forces that.
Momentum and Impulse. Answer Me!!! Forces cause objects to start moving. What keeps an object moving after the force is no longer applied?
Exam Review Exam 4 Momentum Second 6-weeks, Test 1.
Momentum.
Chapter 5: Momentum Momentum: a measure of motion
Momentum Chin-Sung Lin.
Momentum and Impulse Momentum(p)-. Momentum and Impulse Momentum- Newton referred to it as the quantity of motion.
6.3 Newton's Third Law pp
Newton’s Laws of Motion
Unit 09 “The Law of the Conservation of Momentum” Introduction to Problem Solving.
Motion, Forces and Energy Lecture 8: 1- and 2-d Collisions and Rockets
Momentum and Impulse: Lesson 3.  It`s not how fast you are going: it is how fast you stop  To reduce the impact force, increase the stopping distance.
Physics 11 Mr. Jean May 12, The momentum before firing is zero. After firing, the net momentum is still zero because the momentum of the cannon.
Momentum Chapter 2.3.
Definition Formula Units Momentum Vector quantity Direction matches direction of velocity.
Newton’s 3 rd Law For every action….. (The “Action Reaction Law”)
LAWS OF MOTION. Chapter Six: Laws of Motion  6.1 Newton’s First Law  6.2 Newton’s Second Law  6.3 Newton’s Third Law and Momentum.
Force Unit Part 3: Newton’s Third Law. Objectives  Be able to explain Newton’s third law in your own words and give examples  Be able to show that all.
Chapter 6. When objects collide their motion changes and this is the result of a concept called momentum. Momentum = mass x velocity p = mv kgm/s or Ns.
Defining Systems : Has 2 interacting objects, defined for a problem, and is closed and isolated Closed: mass is constant Isolated: no external force.
UNIT TWO: Motion, Force, and Energy  Chapter 4Motion  Chapter 5Force  Chapter 6Newton’s Laws of Motion  Chapter 7 Work and Energy.
Momentum & Impulse For clickers.
Do Now: A 1500 kg car speeds up from 15 m/s to 30 m/s in 6 seconds.
For every force, there is an equal and opposite force.
Physics 101: Lecture 11 Momentum and Impulse
3.1.2 Conservation of Momentum
Newton’s Third Law Section 10.4 Standard 2: Forces
Momentum.
Momentum.
Conservation of Momentum
Topic: Newton’s 3rd Law and Momentum
Momentum.
Ch. 6 Momentum and Impulse
1-D Kinematics Review.
Conservation of momentum
Momentum Contents: New concept Example Whiteboards.
Defining an explosion In an explosion, an internal impulse acts in order to propel the parts of a system (often a single object) into a variety of directions.
Assessment Questions Which of these expresses a vector quantity? 10 kg
6.3 Newton’s Third Law Newton’s Third Law (action- reaction) applies when a force is placed on any object, such as a basketball.
Newton’s 3rd Law of Motion
LAW OF CONSERVATION OF MOMENTUM
the science of collision
Why can’t it stop easily ??
Physics Chapter 6 Equilibrium.
6.3 Newton’s Third Law Newton’s Third Law (action- reaction) applies when a force is placed on any object, such as a basketball.
Presentation transcript:

Initial momentum of entire system is zero (neither object has KE – neither is moving)

The interaction between the two objects must be equal and opposite Note the velocity vectors – why does the cannonball have a greater magnitude of velocity than the cannon?

When the astronaut throws the ball, she goes in the opposite direction

0 = m 1 v 1f + m 2 v 2f

A 2 kg rocket zooms upward at 5 m/s. It is propelled by 1 kg of water shooting downward. How fast does the water shoot out? Momentum Rocket = Momentum Exhaust Momentum Rocket = Momentum Exhaust 0 = m 1 v 1f + m 2 v 2f 0 = (2 kg)(5 m/s) + (1 kg)v 2f