Fan Cart. F N F NA F g Fan Cart F N F NA F g.

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Presentation transcript:

Fan Cart

F N F NA F g

Fan Cart F N F NA F g

Fan Cart F N F NA F g

Fan Cart F N F NA F g =mg

Fan Cart F N =mg F NA F g =mg

Fan Cart F N =mg F NA =.12N F g =mg

Fan Cart F N =mg F NA =.12N F g =mg m=.550 kg

Fan Cart F N =mg F NA =.12N F g =mg Given: m=.550 kg Find a=?m/s/s FRS F=ma F = a m

Fan Cart F N =mg F NA =.12N F g =mg Given: m=.550 kg Find a=?m/s/s FRS F=ma F = a m

Fan Cart F N =mg F NA =.12N F g =mg Given: m=.550 kg Find a=?m/s/s FRS F=ma F = a m

Fan Cart F N =mg F NA =.12N F g =mg Given: m=.550 kg Find a=?m/s/s FRS F=ma F = a m

Fan Cart F N =mg F NA =.12N F g =mg Given: m=.550 kg Find a=?m/s/s FRS F=ma F = a m.12N =.55kg

Fan Cart F N =mg F NA =.12N F g =mg Given: m=.550 kg Find a=?m/s/s FRS F=ma F = a m.12N =.55kg

Fan Cart F N =mg F NA =.12N F g =mg Given: m=.550 kg Find a=?m/s/s FRS F=ma F = a m.12N =.22m/s/s.55kg

Fan Cart F N =mg F NA =.12N F g =mg Given: m=.550 kg Find a=?m/s/s FRS F=ma F = a m.12N =.15m/s/s.80kg

Cart / Falling Object

Cart / Falling Object

Cart / Falling Object

Cart / Falling Object

Cart / Falling Object

Cart / Falling Object FgFg

Cart / Falling Object F g =mg

Cart / Falling Object F g =mg FNFN

Cart / Falling Object F g =mg FNFN FTFT

Cart / Falling Object F g =mg FNFN FTFT

Cart / Falling Object F g =mg FNFN FTFT FTFT

Cart / Falling Object F g =mg FNFN FTFT FTFT Net F =ma F T =ma

Cart / Falling Object F g =mg FNFN FTFT FTFT Net F =m c a F T =m c a

Cart / Falling Object F g =mg FNFN FTFT FTFT Net F =m c a F T =m c a Net F =m f a F g -F T = m f a

Cart / Falling Object F g =mg FNFN FTFT FTFT Net F =m c a F T =m c a Net F =m f a F g -F T = m f a m f g-F T =m f a

Cart / Falling Object F g =mg FNFN FTFT FTFT Net F =m c a F T =m c a Net F =m f a F g -F T = m f a m f g-F T =m f a m f g-m c a=m f a

Cart / Falling Object F g =mg FNFN FTFT FTFT Net F =m c a F T =m c a Net F =m f a F g -F T = m f a m f g-F T =m f a m f g-m c a=m f a m f g=m f a+m c a m f g = a (m f +m c )

Cart / Falling Object F g =mg FNFN FTFT FTFT Net F =m c a F T =m c a Net F =m f a F g -F T = m f a m f g-F T =m f a m f g-m c a=m f a m f g=m f a+m c a m f g = a (m f +m c )

Cart / Falling Object F g =mg FNFN FTFT FTFT NetF X =m c a F T =m c a Net F =m f a F g -F T = m f a m f g-F T =m f a m f g-m c a=m f a m f g=m f a+m c a m f g = a (m f +m c ) Acceleration = Force due gravity on falling object divided by total mass

Cart Falling Object Lab F G – F T = m f a F T =m c a m f g-m c a=m f a m f g=m c a+m f a m f g = (m c +m f )a m f g = a Weight =a (m c +m f ) (combined mass)

Block / Falling Object

Block / Falling Object F N F T F fr F T F G F G =m b g

Block / Falling Object F N F T F fr F T F G F G =m b g

Block / Falling Object F N F T F fr F T F G F G =m b g

Block / Falling Object F N F T F fr F T F G F G =m b g

Block / Falling Object F N F T F fr F T F G =m f g F G =m b g

Block / Falling Object F N F T F fr F T F G =m f g F G =m b g

Block / Falling Object F N F T F fr F T Net F =m b a F T -F fr =m b a F G =m f g F G =m b g

Block / Falling Object F N F T F fr F T Net F =m b a F T -F fr =m b a F G =m f g F T -  F N =m b a F G =m b g

Block / Falling Object F N F T F fr F T Net F =m b a F T -F fr =m b a F G =m f g F T -  F N =m b a Net F =m f a F T -  m b g=m b a m f g-F T =m f a m f g-m f a=F T F G =m b g

Block / Falling Object F N F T F fr F T Net F =m b a F T -F fr =m b a F G =m f g F T -  F N =m b a Net F =m f a F T -  m b g=m b a m f g-F T =m f a m f g-m f a=F T F G =m b g

Block / Falling Object F N F T F fr F T Net F =m b a F T -F fr =m b a F G =m f g F T -  F N =m b a Net F =m f a F T -  m b g=m b a m f g-F T =m f a m f g-m f a=F T F G =m b g

Block / Falling Object F N F T F fr F T Net F =m b a F T -F fr =m b a F G =m f g F T -  F N =m b a Net F =m f a F T -  m b g=m b a m f g-F T =m f a m f g-m f a-  m b g=m b a m f g-m f a=F T F G =m b g

Block / Falling Object F N F T F fr F T Net F =m b a F T -F fr =m b a F G =m f g F T -  F N =m b a Net F =m f a F T -  m b g=m b a m f g-F T =m f a m f g-m f a-  m b g=m b a m f g-m f a=F T m f g-  m b g=m b a+m f a F G =m b g

Block / Falling Object F N F T F fr F T Net F =m b a F T -F fr =m b a F G =m f g F T -  F N =m b a Net F =m f a F T -  m b g=m b a m f g-F T =m f a m f g-m f a-  m b g=m b a m f g-m f a=F T m f g-  m b g=m b a+m f a m f g-  m b g = a (m f g-  m b g)=a (m f +m c ) F G =m b g

Block Falling Object F G – F T = m f a F T -F fr =m b a m f g-m b a-  m b g=m f a F T = m b a+F fr F T = m b a +  m b g m f g-  m b g=m f a + m b a m f g –  m b g = (m b +m f )a m f g-  m b g = a Weight -Friction =a (m b +m f ) (combined mass)

Lab Frictionless incline

Lab Frictionless incline

Lab Frictionless incline F N F g

Lab Frictionless incline F N  F gpara F gperp

Lab Frictionless incline F N = mgcos   F gll =mgsin  F gper = mgcos 

Lab 4 Frictionless incline F gpara = mgsin  ma F N = F gperp = mgcos  gsin  a The acceleration of a cart on a frictionless incline is dependent on the acceleration due to gravity and the sin of the incline angle. It is independent of the mass of the object.

Lab 5 Block on incline involving friction

Lab 5 Block on incline involving friction

Lab 5 Block on incline involving friction

Lab 5 Block on incline involving friction F g =mg

Lab 5 Block on incline involving friction F g =mg

Lab 5 Block on incline involving friction F g =mg FNFN

Lab 5 Block on incline involving friction F g =mg F gy FNFN

Lab 5 Block on incline involving friction F g =mg F gper FNFN

Lab 5 Block on incline involving friction F g =mg F gy FNFN F gpara

Lab 5 Block on incline involving friction F g =mg F gper FNFN F gpara

Lab 5 Block on incline involving friction F g =mg F gperp FNFN F gpara F fr

Lab 5 Block on incline involving friction F g =mg F gy FNFN F gx F fr Perpendicular

Lab 5 Block on incline involving friction F g =mg F gy FNFN F gx F fr Perpendicular Parallel

Lab 5 Block on incline involving friction F g =mg F gy FNFN F gx F fr Perpendicular Parallel mgcos 

Lab 5 Block on incline involving friction F g =mg F gy FNFN F gx F fr Perpendicular Parallel mgcos  mgsin 

Lab 5 Block on incline involving friction F g =mg F gy FNFN F gx F fr Perpendicular Parallel mgcos  mgsin  mgcos 

Lab 5 Block on incline involving friction F g =mg F gy FNFN F gx F fr Perpendicular Parallel mgcos  mgsin  mgcos  F fr =  F N

Lab 5 Block on incline involving friction F g =mg F gy FNFN F gx F fr Perpendicular Parallel mgcos  mgsin  mgcos  F fr =  F N  mgcos 

Lab 5 Block on incline involving friction F g =mg F gy FNFN F gx F fr Perpendicular Parallel mgcos  mgsin  mgcos  F fr =  F N  mgcos  mgcos  =mgcos 

Lab 5 Block on incline involving friction F g =mg F gy FNFN F gx F fr Perpendicular Parallel mgcos  mgsin  mgcos   f F gx = Static Friction mgcos  F fr =  F N  mgcos  mgcos  =mgcos 

Lab 5 Block on incline involving friction F g =mg F gy FNFN F gx F fr Perpendicular Parallel mgcos  mgsin  mgcos   f F gx = Static Friction mgcos  F fr =  F N  mgcos  mgcos  =mgcos  If F gx > Static Friction mgsin  -  mgcos  =ma

Lab 5 Block on incline involving friction F g =mg F gy FNFN F gx F fr Perpendicular Parallel mgcos  mgsin  mgcos   f F gx = Static Friction mgcos  F fr =  F N  mgcos  mgcos  =mgcos  If F gx > Static Friction mgsin  -  mgcos  =ma

Lab 5 Block on incline involving friction Net F = Perpendicular to incline

Lab 5 Block on incline involving friction Net F = 0 Perpendicular to incline

Lab 5 Block on incline involving friction Net F = 0 Perpendicular to incline F gy =F N = mgcos 

Lab 5 Block on incline involving friction  F y = 0 Perpendicular to incline F perp =FN = mgcos 

Lab 5 Block on incline involving friction  F y = 0 Perpendicular to incline F perp =FN = mgcos 

Lab 5 Block on incline involving friction Fnet = 0 Perpendicular to incline F perp =F N = mgcos   F x = ____ if Force due to gravity parallel to incline equals static friction.

Lab 5 Block on incline involving friction F net = 0 Perpendicular to incline F perp =F N = mgcos  F Net = 0 if Force due to gravity parallel to incline equals static friction.

Lab 5 Block on incline involving friction F net = 0 Perpendicular to incline F perp =F N = mgcos  F Net = 0 if Force due to gravity parallel to incline equals static friction. F parallel =

Lab 5 Block on incline involving friction F net = 0 Perpendicular to incline F perp =F N = mgcos  F Net = 0 if Force due to gravity parallel to incline equals static friction. F parallel = F fr

Lab 5 Block on incline involving friction F net = 0 Perpendicular to incline F perp =F N = mgcos  F Net = 0 if Force due to gravity parallel to incline equals static friction. F parallel = F fr mgsin  ==  mgcos  sin  =  cos  sin  =  tan  cos 

Lab 5 Block on incline involving friction F net = 0 Perpendicular to incline F perp =F N = mgcos  F Net = 0 if Force due to gravity parallel to incline equals static friction. F parallel = F fr mgsin  ==  mgcos  sin  =  cos  sin  =  tan  cos 

Lab 5 Block on incline involving friction F net = 0 Perpendicular to incline F perp =F N = mgcos  F Net = 0 if Force due to gravity parallel to incline equals static friction. F parallel = F fr mgsin  ==  mgcos  sin  =  cos  sin  =  tan  cos 

Lab 5 Block on incline involving friction F net = 0 Perpendicular to incline F perp =F N = mgcos  F Net = 0 if Force due to gravity parallel to incline equals static friction. F parallel = F fr mgsin  ==  mgcos  sin  =  cos  sin  =  tan  cos 

Lab 5 Block on incline involving friction F net = 0 Perpendicular to incline F perp =F N = mgcos  F Net = 0 if Force due to gravity parallel to incline equals static friction. F parallel = F fr mgsin  ==  mgcos  sin  =  cos  sin  =  tan  cos 

Lab 5 Block on incline involving friction F net = 0 Perpendicular to incline F perp =F N = mgcos  F net = if Force due to gravity parallel greater than incline friction F gparallel - F fr = ma mgsin  –  mgcos  ma gsin  –  cos  a

Lab 5 Block on incline involving friction F net = 0 Perpendicular to incline F perp =F N = mgcos  F net = if Force due to gravity parallel greater than incline friction F gparallel - F fr = ma mgsin  –  mgcos  ma gsin  –  cos  a

Lab 5 Block on incline involving friction F net = 0 Perpendicular to incline F perp =F N = mgcos  F net = if Force due to gravity parallel greater than incline friction F gparallel - F fr = ma mgsin  –  mgcos  ma gsin  –  cos  a

Lab 5 Block on incline involving friction F net = 0 Perpendicular to incline F perp =F N = mgcos  F net = if Force due to gravity parallel greater than incline friction F gparallel - F fr = ma mgsin  –  mgcos  ma gsin  –  cos  a

Lab 5 Block on incline involving friction F net = 0 Perpendicular to incline F perp =F N = mgcos  F net = ma if Force due to gravity parallel greater than incline friction F gparallel - F fr = ma mgsin  –  mgcos  ma gsin  –  cos  a

Lab 5 Block on incline involving friction F net = 0 Perpendicular to incline F perp =F N = mgcos  F net = ma if Force due to gravity parallel greater than incline friction F gparallel - F fr = ma mgsin  –  mgcos  ma gsin  –  cos  a

Lab 5 Block on incline involving friction F net = 0 Perpendicular to incline F perp =F N = mgcos  F net = ma if Force due to gravity parallel greater than incline friction F gparallel - F fr = ma mgsin  –  mgcos  ma gsin  –  cos  a

Lab 5 Block on incline involving friction F net = 0 Perpendicular to incline F perp =F N = mgcos  F net = ma if Force due to gravity parallel greater than incline friction F gparallel - F fr = ma mgsin  –  mgcos  ma gsin  –  cos  a

Lab 5 Block on incline involving friction F net = 0 Perpendicular to incline F perp =F N = mgcos  F net = ma if Force due to gravity parallel greater than incline friction F gparallel - F fr = ma mgsin  –  mgcos  ma gsin  –  cos  a

Lab 5 Block on incline involving friction F net = 0 Perpendicular to incline F perp =F N = mgcos  F net = ma if Force due to gravity parallel greater than incline friction F gparallel - F fr = ma mgsin  –  mgcos  ma gsin  –  cos  a

Lab 5 incline involving friction Force down – Friction = Net force mgsin  mgcos  ma gsin  - -  gcos  = a The acceleration of a cart incline is dependent on the acceleration due to gravity and angle of the incline and the coeffiecient of friction but not the mass of the object.

Lab 5 incline involving friction Force down – Friction = Net force mgsin  mgcos  ma gsin  - -  gcos  = a The acceleration of a cart incline is dependent on the acceleration due to gravity and angle of the incline and the coeffiecient of friction but not the mass of the object.

F net = F g heavy - F glight (m H +m L )a = m H g-m L g

F net = F g heavy - F glight (m H +m L ) a = m H g-m L g a = (m H g-m L g) (m H +m L )

Atwoods Pulley F net = F g heavy - F glight (m H +m L ) a = m H g-m L g a = (m H g-m L g) (m H +m L ) a = (Weight H – Weight L) ( total mass )

Atwoods Pulley F net = F g heavy - F glight (m H +m L ) a = m H g-m L g a = (m H g-m L g) (m H +m L ) a = (Weight H – Weight L) ( total mass )

Block on Incline Falling Mass

mg

Block on Incline Falling Mass mg mgsinf

Block on Incline Falling Mass mg mgsin 

Block on Incline Falling Mass mg mgsin   mgcos 

Block on Incline Falling Mass mg mgsin   mgcos  FTFT

Block on Incline Falling Mass mg mgsin   mgcos  FTFT mg

Block on Incline Falling Mass mg mgsin   mgcos  FTFT mfgmfg FTFT

Block on Incline Falling Mass mg mgsin   mgcos  FTFT mfgmfg FTFT mfgmfg

Block on Incline Falling Mass mg mgsin   mgcos  FTFT mfgmfg FTFT m f g - mgsin 

Block on Incline Falling Mass mg mgsin   mgcos  FTFT mfgmfg FTFT m f g – mgsin  mgcos 

Block on Incline Falling Mass mg mgsin   mgcos  FTFT mfgmfg FTFT m f g – mgsin  mgcos  m  m f  a

Block on Incline Falling Mass mg mgsin   mgcos  FTFT mfgmfg FTFT m f g – mgsin  mgcos  m  m f  a Weight of Falling

Block on Incline Falling Mass mg mgsin   mgcos  FTFT mfgmfg FTFT m f g – mgsin  mgcos  m  m f  a Weight of Falling - Force parallel

Block on Incline Falling Mass mg mgsin   mgcos  FTFT mfgmfg FTFT m f g – mgsin  mgcos  m  m f  a Weight of Falling - Force parallel – Friction

Block on Incline Falling Mass mg mgsin   mgcos  FTFT mfgmfg FTFT m f g – mgsin  mgcos  m  m f  a Weight of Falling - Force parallel – Friction = Net Force

Block on Incline Falling Mass mg mgsin   mgcos  FTFT mfgmfg FTFT m f g – mgsin  mgcos  m  m f  a m f g – mgsin  mgcos  a  m  m f  Weight of Falling - Force parallel – Friction = Net Force