Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 1 Lecture 4 - Transverse Optics II ACCELERATOR PHYSICS MT 2014 E. J. N. Wilson.

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Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 1 Lecture 4 - Transverse Optics II ACCELERATOR PHYSICS MT 2014 E. J. N. Wilson

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 2 Contents of previous lecture - Transverse Optics I  Transverse coordinates  Vertical Focusing  Cosmotron  Weak focusing in a synchrotron  The “n-value”  Gutter  Transverse ellipse  Cosmotron people  Alternating gradients  Equation of motion in transverse co- ordinates

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 3 Lecture 4 - Transverse Optics II Contents  Equation of motion in transverse co- ordinates  Check Solution of Hill  Twiss Matrix  Solving for a ring  The lattice  Beam sections  Physical meaning of Q and beta  Smooth approximation

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 4 Equation of motion in transverse co- ordinates  Hill’s equation (linear-periodic coefficients) –where at quadrupoles –like restoring constant in harmonic motion  Solution (e.g. Horizontal plane)  Condition  Property of machine  Property of the particle (beam)   Physical meaning (H or V planes) Envelope Maximum excursions

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 5 Check Solution of Hill  Differentiate substituting  Necessary condition for solution to be true so  Differentiate again add both sides

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 6 Continue checking  The condition that these three coefficients sum to zero is a differential equation for the envelope alternatively

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 7  All such linear motion from points 1 to 2 can be described by a matrix like:  To find elements first use notation  We know  Differentiate and remember  Trace two rays one starts “cosine”  The other starts with “sine”  We just plug in the “c” and “s” expression for displacement an divergence at point 1 and the general solutions at point 2 on LHS  Matrix then yields four simultaneous equations with unknowns : a b c d which can be solved Twiss Matrix

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 8 Twiss Matrix (continued)  Writing  The matrix elements are  Above is the general case but to simplify we consider points which are separated by only one PERIOD and for which  The “period” matrix is then  If you have difficulty with the concept of a period just think of a single turn.

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 9 Twiss concluded  Can be simplified if we define the “Twiss” parameters:  Giving the matrix for a ring (or period)

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 10 The lattice

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 11 Beam sections after,pct

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 12 Physical meaning of Q and 

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 13 Smooth approximation

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 14 Principal trajectories

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 15 Effect of a drift length and a quadrupole Quadrupole Drift length

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 16 Focusing in a sector magnet

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 17 The lattice (1% of SPS)

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 18 Calculating the Twiss parameters THEORYCOMPUTATION (multiply elements) Real hard numbers Solve to get Twiss parameters:

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 19 Meaning of Twiss parameters   is either : » Emittance of a beam anywhere in the ring » Courant and Snyder invariant fro one particle anywhere in the ring

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 20 Example of Beam Size Calculation  Emittance at 10 GeV/c

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 21 Summary  Equation of motion in transverse co- ordinates  Check Solution of Hill  Twiss Matrix  Solving for a ring  The lattice  Beam sections  Physical meaning of Q and beta  Smooth approximation

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 22 Further reading  The slides that follow may interest students who would like to see a formal derivation of Hill’s Equation from Hamiltonian Mechanics

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 23 Relativistic H of a charged particle in an electromagnetic field  Remember from special relativity: i.e. the energy of a free particle  Add in the electromagnetic field »electrostatic energy »magnetic vector potential has same dimensions as momentum

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 24 Hamiltonian for a particle in an accelerator  Note this is not independent of q because  Montague (pp 39 – 48) does a lot of rigorous, clever but confusing things but in the end he just turns H inside out  is the new Hamiltonian with s as the independent variable instead of t (see M 48)  Wilson obtains »assumes curvature is small »assumes »assumes magnet has no ends »assumes small angles »ignores y plane  Dividing by  Finally (W Equ 8)

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 25 Multipoles in the Hamiltonian  We said contains x (and y) dependance  We find out how by comparing the two expressions:  We find a series of multipoles:  For a quadrupole n=2 and:

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 26 Hill’s equation in one ( or two) lines  Hamilton’s equations give an equation of motion (remember independent coordinate is now s not t ) and:

Lecture 4 - E. Wilson - 23 Oct 2014 –- Slide 27 Other interesting forms In x plane Small divergences: Substitute a Taylor series: Multipoles each have a term: Quadrupoles: But: