Discrete and Continuous Data Part 2 Remember back from an earlier lesson where Genaro worked math problems and raised $3 for each correct answer. This.

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Presentation transcript:

Discrete and Continuous Data Part 2 Remember back from an earlier lesson where Genaro worked math problems and raised $3 for each correct answer. This can be represented by the function g(p) = 3p Mrs. Snurd, the sponsor, is changing the rules of the fund raiser to make it easier to determine how much each student should collect by rounding the number of correct answers to the nearest ten. For example, if Genaro answered 22 problems correct, then 20 would be to the nearest ten. Also 200 is the maximum correct answers allowed.

Discrete and Continuous Data Part 2 g(p) = 3p Round correct problems to nearest ten Maximum correct is 200 problems. (1)Use the function and the new guidelines above to find the domain for p. Discuss with your group. The answer is D = {0, 10, 20, 30, …..200} The set of values for each domain element is called the range of the function. (2) With your group discuss what values the range could have. Hint: Think minimum to maximum. The answer is R = {0, 30, 60, 90, ……600} (3) List all the ordered pairs for this function. (0,0), (10, 30), (20, 60), (30, 90), ……(200, 600)

Discrete and Continuous Data Part 2 g(p) = 3p Round correct problems to nearest ten Maximum correct is 200 problems. (4) Use your ordered pairs to determine the following: p minimum p maximum p scale g(p) minimum g(p) maximum g(p) scale

Discrete and Continuous Data Part 2 (4) Use your ordered pairs to determine the following: p minimum 0 p maximum 200 p scale10 or 20 g(p) minimum0 g(p) maximum600 g(p) scale30 or 60 (5) Now sketch the function by graphing the points. (6) Is the graph discrete or continuous. Explain your reasoning. Answer should be discrete.

QUICK REVIEW Consider this scenario: Davis, a new student and cross-country runner, missed the earlier fundraiser. He comes up with an idea to run as many miles as he can in an hour. Some of his sponsors give him a set amount of money totaling $30 while others decide to pay him $6 per mile he runs to the nearest whole mile. (7) With your group, write a function rule for this situation. Answer is a(m) = 6m + 30

QUICK REVIEW a(m) = 6m + 30 (8) With your group, determine the domain and range of this function…use your brains. Explain your reasoning. The domain could be as little as zero and as high as 13 for a marathon runner so D = {0, 1, 2, 3….13} The range minimum would be 30 with the maximum being 108 if 13 is the highest domain value so R = {30, 36, 42, ….108}

QUICK REVIEW a(m) = 6m + 30 (9) With your group, how many miles will Davis have to run to earn $54, $93, $150? For $54, Davis needs to run 4 miles. For $93, Davis needs to run 10.5 miles BUT that is NOT possible rounding to the nearest whole mile. For $150, Davis would have to run 20 miles which is NOT possible in an hour.