10/20 - Warm Up #5 Find either the correct element or the correct electron configuration for the following: Nitrogen 1s 2 2s 2 2p 6 3s 2 3p 3 Magnesium.

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10/20 - Warm Up #5 Find either the correct element or the correct electron configuration for the following: Nitrogen 1s 2 2s 2 2p 6 3s 2 3p 3 Magnesium Which element do you think has a larger atomic size: Nitrogen or Phosphorus. Why?

D AND F ORBITALS (AND EXCEPTIONAL ELEMENTS) NOBLE GAS NOTATION Orbital Notation Part II

Review S, P, D, F Orbitals Ex. Nitrogen (7) FOLLOW ATOMIC NUMBER start with 1, and follow it until you get to your destination 1s 2 2s 2 2p 3 Check: = 7 2p 3 Row/ Period Section Elements # in that section

Rules of the Orbitals Aufbau Principle – electrons occupy lowest energy level first [see pic] Pauli Exclusion Principle – two electrons per orbital max  Spin in opposite directions  Spin = arrows up and down Hund’s Rule – must all spin in one direction first, THEN fill in opposite spin second

Example: Titanium Row: 4 Section: D Seat: 2 So it should be: 4d 2 BUT IT ISN’T!!!

When dealing with D-section: It’s always (n-1) section So if in row 4 (n = 4) D section = 3d 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 2 = Titanium Check : = 22

Bigger Elements Selenium = 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 10 4p 4 THAT’S WAY TOO LONG!!! Easier way: Use NOBLE GAS before element [Noble Gasses: He, Ne, Ar, Kr, Xe, Rn]

Noble Gas Notation For Selenium (Se – 34): Noble Gas before: Ar So: [Ar] 4s 2 3d 10 4p 4 Check: Ar = = 34 This form = Noble Gas Notation

The F-Section F section = lanthanides and actinides. Start in sixth row (n = 6) BUT: START with 4f F-section = (n-2) Max: 14 electrons

Things to Note: [Xe] 6s 2 5d 1 4f 2 Notice: it’s NOT 6f 2 ! For F-Section: (n-2) So: [Xe]6s 2 5d 1 4f 2 = Cerium (Ce)

Look at La and Ce Look for break off La = 5d1  So [Xe] 6s 2 5d 1 Ce = 4f 1 BUT pass through La first!  So…[Xe] 6s 2 5d 1 4f 1

Quick Quiz #2 Express the following in Noble Gas configuration: Cadmium Iodine [Kr] 5s 1 [Xe] 6s 2 5d 1 4f 2