© 2015 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 37.

Slides:



Advertisements
Similar presentations
Conversion and Reactor sizing
Advertisements

Conversion and Reactor Sizing
Modelling & Simulation of Chemical Engineering Systems
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 21.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 15.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 11.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 3.
Development of Dynamic Models Illustrative Example: A Blending Process
SABIC Chair in Catalysis at KAU Chemical Reaction Engineering Dr. Yahia Alhamed.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 10.
THEORETICAL MODELS OF CHEMICAL PROCESSES
© 2015 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 32.
ISOTHERMAL REACTOR DESIGN
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 22.
A First Course on Kinetics and Reaction Engineering
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 28.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 23.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 11.
© 2015 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 31.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 19.
Mole balance for chemical reaction engineering (Design Equations for reactors) Lec 3 week 3.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 14.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 26.
© 2015 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 33.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 12.
© 2015 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 31.
Lecture 1: Kinetics of Substrate Utilization and Product Formation
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 13.
© 2015 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 34.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 12.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 23.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 17.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 29.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 4.
Isothermal Reactor Design
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 30.
Chapter 13 Chemical Equilibrium The state where the concentrations of all reactants and products remain constant with time. On the molecular level, there.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 1.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 13.
Energy Balance on Reactive Processes
Conversion and Reactor Sizing Lec 4 week 4. Definition of Conversion for the following reaction The reaction can be arranged as follows: how far the above.
© 2015 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 34.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 14.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 17.
© 2015 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 33.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 30.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 25.
© 2015 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 37.
© 2015 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 36.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 24.
© 2015 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 35.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 3.
© 2016 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 38.
© 2014 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 4.
CHAPTER 3 material balance part iI
 Chemical Equilibrium occurs when opposing reactions are proceeding at equal rates.  When the forward reaction equals the reverse reaction.  It results.
© 2016 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 40.
EQUILIBRIUM. Equilibrium Constant (K Values)  The equilibrium constant (Keq) is a number showing the relationship between the concentration of the products.
ChE 402: Chemical Reaction Engineering
Review: What size reactor(s) to use?
A First Course on Kinetics and Reaction Engineering
A First Course on Kinetics and Reaction Engineering
A First Course on Kinetics and Reaction Engineering
A First Course on Kinetics and Reaction Engineering
A First Course on Kinetics and Reaction Engineering
Process Equipment Design Chemical Reactors
Mustafa Nasser, PhD, MSc, BSc Chemical Engineering
Kinetics Patrick Cable, Dat Huynh, Greg Kalinyak, Ryan Leech, Wright Makambi, Ronak Ujla.
Steady-state Nonisothermal reactor Design Part I
13. Reactor Engineering: Reactor Design
Presentation transcript:

© 2015 Carl Lund, all rights reserved A First Course on Kinetics and Reaction Engineering Class 37

Where We’re Going Part I - Chemical Reactions Part II - Chemical Reaction Kinetics Part III - Chemical Reaction Engineering Part IV - Non-Ideal Reactions and Reactors ‣ A. Alternatives to the Ideal Reactor Models  33. Axial Dispersion Model  D and 3-D Tubular Reactor Models  35. Zoned Reactor Models  36. Segregated Flow Models  37. Overview of Multi-Phase Reactors ‣ B. Coupled Chemical and Physical Kinetics  38. Heterogeneous Catalytic Reactions  39. Gas-Liquid Reactions  40. Gas-Solid Reactions

Reactors Other Than CSTRs and PFRs When reactants and/or products are present in two or more phases in a reactor, it is generally necessary to write mole and energy balances on each phase In some cases simple stirred tanks or tubular packed beds are used for multi-phase reactions In other cases, more specialized reactors are used ‣ For gas-solid or solid-catalyzed gas phase reactions  fluidized bed reactors  riser reactors ‣ For solid-catalyzed gas-liquid reactions  trickle bed reactors  slurry reactors (also for solid-catalyzed liquid reactions) ‣ For gas-liquid reactions  spray tower reactors  bubble column reactors ‣ Combined reaction and separation  Reactive distillation columns  Membrane reactors ‣ Laminar flow reactors

Questions?

A gas mixture containing CO 2 is fed to an isothermal, steady state CSTR. A solution containing an amine, NH 2 R, is also fed to the reactor. The agitator system for the reactor has been designed so that the gas phase may be treated as perfectly mixed. The gas is dispersed as bubbles in the liquid, which is also perfectly mixed. The inlet molar flow rates of all species are known and constant, as are the liquid volume, the gas volume and the interfacial area per volume of liquid, A V. The inlet and outlet volumetric flow rates may be taken to be equal and known. None of the gases except CO 2 are soluble in the solution, and none of the components of the solution are volatile. When CO 2 dissolves in the solution, it reacts with the amine to form an adduct according to equation (1). The rate expression for the reaction is given in equation (2) where square brackets denote solution phase concentrations, and the rate coefficient is known. If the reaction rate is very, very slow, then the gas phase and solution phase CO 2 will be equilibrated according to Henry’s Law, equation (3), where h is the known Henry’s law constant. Write the mole balance design equations needed to calculate the amount of CO 2 removed from the gas phase by this reactor. NH 2 R + CO 2 → CO 2 :NH 2 R(1) (2) (3)

How many sets of design equations will be needed? Solution

How many sets of design equations will be needed? ‣ There are two phases and reactants and/or products are present in both phases, so two sets of design equations will be needed What are the two sets of design equations for? Solution

How many sets of design equations will be needed? ‣ There are two phases and reactants and/or products are present in both phases, so two sets of design equations will be needed What are the two sets of design equations for? ‣ One set for the gas phase and one set for the liquid phase What design equations will be needed for the gas phase? Solution

How many sets of design equations will be needed? ‣ There are two phases and reactants and/or products are present in both phases, so two sets of design equations will be needed What are the two sets of design equations for? ‣ One set for the gas phase and one set for the liquid phase What design equations will be needed for the gas phase? ‣ The reactor is isothermal, so the mole balance design equations can be solved independently of the energy balance ‣ In this problem, energy balances will not be needed to answer the question ‣ Only mole balances are needed ‣ The only reactant or product in the gas phase is CO 2, so a mole balance on CO 2 is needed. What assumptions can we make about the gas phase when writing its mole balance? Solution

How many sets of design equations will be needed? ‣ There are two phases and reactants and/or products are present in both phases, so two sets of design equations will be needed What are the two sets of design equations for? ‣ One set for the gas phase and one set for the liquid phase What design equations will be needed for the gas phase? ‣ The reactor is isothermal, so the mole balance design equations can be solved independently of the energy balance ‣ In this problem, energy balances will not be needed to answer the question ‣ Only mole balances are needed ‣ The only reactant or product in the gas phase is CO 2, so a mole balance on CO 2 is needed. What assumptions can we make about the gas phase when writing its mole balance? ‣ It is perfectly mixed, so we can write the mole balance by analogy to the CSTR design equations, except there will be an additional net input term ‣ The reactor is at steady state, so we do not need accumulation terms ‣ The second reactant is not present in the gas phase, so there is no reaction (generation) term Write the mole balance on CO 2 for the gas phase Solution

How many sets of design equations will be needed? ‣ There are two phases and reactants and/or products are present in both phases, so two sets of design equations will be needed What are the two sets of design equations for? ‣ One set for the gas phase and one set for the liquid phase What design equations will be needed for the gas phase? ‣ The reactor is isothermal, so the mole balance design equations can be solved independently of the energy balance ‣ In this problem, energy balances will not be needed to answer the question ‣ Only mole balances are needed ‣ The only reactant or product in the gas phase is CO 2, so a mole balance on CO 2 is needed. What assumptions can we make about the gas phase when writing its mole balance? ‣ It is perfectly mixed, so we can write the mole balance by analogy to the CSTR design equations, except there will be an additional net output term ‣ The reactor is at steady state, so we do not need accumulation terms ‣ The second reactant is not present in the gas phase, so there is no reaction (generation) term Write the mole balance on CO 2 for the gas phase ‣ Solution

What design equations will be needed for the liquid phase?

‣ Again, an energy balance is not needed ‣ There are two reactants and one product, mole balances can be written for each of these three species What assumptions can we make about the liquid phase when writing its mole balances?

What design equations will be needed for the liquid phase? ‣ Again, an energy balance is not needed ‣ There are two reactants and one product, mole balances can be written for each of these three species What assumptions can we make about the liquid phase when writing its mole balances? ‣ As with the gas phase, it is perfectly mixed, so we can model the equations after the CSTR design equations, except for CO 2 there will be an extra net input term ‣ The reactor is at steady state, so there are no accumulation terms Write the mole balances for the liquid phase

What design equations will be needed for the liquid phase? ‣ Again, an energy balance is not needed ‣ There are two reactants and one product, mole balances can be written for each of these three species What assumptions can we make about the liquid phase when writing its mole balances? ‣ As with the gas phase, it is perfectly mixed, so we can model the equations after the CSTR design equations, except for CO 2 there will be an extra net input term ‣ The reactor is at steady state, so there are no accumulation terms Write the mole balances for the liquid phase ‣ Determine the type of the design equations and what will be needed to solve them numerically

What design equations will be needed for the liquid phase? ‣ Again, an energy balance is not needed ‣ There are two reactants and one product, mole balances can be written for each of these three species What assumptions can we make about the liquid phase when writing its mole balances? ‣ As with the gas phase, it is perfectly mixed, so we can model the equations after the CSTR design equations, except for CO 2 there will be an extra net input term ‣ The reactor is at steady state, so there are no accumulation terms Write the mole balances for the liquid phase ‣ Determine the type of the design equations and what will be needed to solve them numerically ‣ The design equations are a set of four non-linear algebraic equations ‣ They can be solved numerically for four unknowns ‣ To do so one must provide  guesses for the values of the unknowns  code that is given values for the unknowns and uses those values to evaluate the left hand sides of the four equations above Show how to solve the design equations by providing the necessary info

‣ To do so one must provide  guesses for the values of the unknowns  code that is given values for the unknowns and uses those values to evaluate the left hand sides of the four equations above Show how to solve the design equations by providing the necessary info ‣ The following quantities are known according to the problem statement: V l, A V, ṅ 0 CO2,g, k, ṅ 0 NH2R,l ‣ Thus, the following quantities are unknown: ṅ CO2,g, N, ṅ CO2,l, [NH 2 R], [CO 2 ], ṅ NH2R,l and ṅ CO2:NH2R,l ‣ We cannot choose any 4 unknowns to be solved for numerically  The liquid and gas phase amounts of CO 2 are not independent; they are related by Henry’s law  The liquid phase concentrations are related to the outlet liquid molar flow rates ‣ Therefore, choose to solve the design equations for ṅ CO2,g, N, ṅ NH2R,l and ṅ CO2:NH2R,l  We must provide guesses for these four unknowns  We must provide code that uses the value of these four unknowns to evaluate the equations above  That code, then, must calculate ṅ CO2,l, [NH 2 R] and [CO 2 ]

‣ Calculation of [NH 2 R] ‣ Calculation of [CO 2 ] ‣ Calculation of Show any additional calculations that will need to be performed after the design equations have been solved

‣ Calculation of [NH 2 R] ‣ Calculation of [CO 2 ] ‣ Calculation of Show any additional calculations that will need to be performed after the design equations have been solved ‣ The values of the four unknowns will be known ‣ They can be used to calculate the three quantities above ‣ The amount of CO 2 removed, in moles per time, can be calculated either of two ways  It will equal ṅ CO2,l + ṅ CO2:NH2R,l  Or, it will equal ṅ 0 CO2,g - ṅ CO2,g The assumption of equilibrium between the bulk liquid and bulk gas phase CO 2 greatly simplified the necessary equations ‣ Essentially it assumed that the rate of dissolution of CO 2 in the liquid was instantaneous ‣ Form small groups and discuss how you think the physics of the problem (or the equations needed to solve it) would change if the rate of reaction and the rate of dissolution were comparable ‣ Unit 39 considers this very issue

Where We’re Going Part I - Chemical Reactions Part II - Chemical Reaction Kinetics Part III - Chemical Reaction Engineering Part IV - Non-Ideal Reactions and Reactors ‣ A. Alternatives to the Ideal Reactor Models  33. Axial Dispersion Model  D and 3-D Tubular Reactor Models  35. Zoned Reactor Models  36. Segregated Flow Models  37. Overview of Multi-Phase Reactors ‣ B. Coupled Chemical and Physical Kinetics  38. Heterogeneous Catalytic Reactions  39. Gas-Liquid Reactions  40. Gas-Solid Reactions