You will use the sine and cosine ratio to find the sides and angles of a right triangles Pardekooper
sine = opposite Pardekooper hypotenuse cosine = adjacent hypotenuse
Lets try setting up for sin C Pardekooper sin = opposite hypotenuse sin =
Lets try setting up for cos C Pardekooper cos = adjacent hypotenuse cos =
Lets try setting up for cos C Pardekooper cos = adjacent hypotenuse cos =
Lets try setting up for sin C Pardekooper sin = opposite hypotenuse sin =
Solve right triangle ABC if b=32, A=25 o, and C=90 o a b=32 c = 25 o = 90 o = 65 o A B C c =15 32 AA BB CC Pardekooper Remember this problem from o 15
Solve right triangle ABC if b=32, A=25 o, and C=90 o a b=32 c = 25 o = 90 o = 65 o A B C c =15 32 AA BB CC Pardekooper sin = opposite hypotenuse sin25 0 = o c c c c sin25 0 = 15 c = 15 / sin
Now lets find the hypotenuse to the nearest whole number. C Pardekooper cos = adjacent hypotenuse cos = c c cos58 0 = 7 7 cos58 0 c c 13
Pardekooper Here comes the assignment
Assignment Workbook Page 403 all