LargerScientistsUnits e- config 101 Is it possible? Potpourri $ 200 $ 200$200 $ 200 $ 200 $400 $ 400$400 $ 400$400 $600 $ 600$600 $ 600 $ 600 $ 600 $800 $ 800$800 $ 800 $ 800 $ 800 $ 1000$1000 $ 1000 $ 1000 $ 1000 $ 1000

Smaller So many rules Trends e- config 201 Quantum #More #s $ 400 $ 400 $ 400 $ 400 $ 400 $ 400 $ 800 $ 800 $ 800 $ 800 $ 800 $ 800 $ 1200 $ 1200 $ 1200 $ 1200 $ 1200 $ 1200 $ 1600 $ 1600 $ 1600 $ 1600 $ 1600 $ 1600 $ 2000 $ 2000 $ 2000 $ 2000 $ 2000 $ 2000

Final Jeopardy Using the Equations

Final Jeopardy 3.77 * J A photon of green light has a wavelength of 525nm. Calculate the energy of the photon (in J).

$200 Si Larger Atomic radius of Si or Cl

$400 red Larger λ of red light or green light

$600 green Larger ν of red light or green light

$800 radio Larger λ of radio waves or γ rays

$1000 Ionic radius of O 2- Larger atomic radius of O or ionic radius of O 2-

$200 Mendeleev

$400 Bohr

$600 Einstein

$800 Schrödinger

$1000 Heisenberg

$200 m or nm λ

$400 Hz or 1/s or s -1 ν

$600 J E

$800 m/s c

$1000 J*s h

$200 Li 1s 2 2s 1

$400 1s 2 2s 2 2p 2 C

$600 Al [Ne] 3s 2 3p 1

$800 Br [Ar] 4s 2 3d 10 4p 5

$1000 Sg [Rn] 7s 2 5f 14 6d 4

$200 Yes ½

$400 No (m s can only be +½ or -½)

$600 Yes 2 0 +½

$800 Yes 3 2 -½

$1000 No (l values range from 0 to n-1) 2 1 +½

$200 anion The name for a negative ion

$400 6 S has this # of valence e-

$ Ca ions have this charge

$800 Wave-like and particle-like (matter) Light can exhibit a duality of these two properties

$1000 Quanta Planck identified that energy comes in packets called what?

$400 Ca Smaller electronegativity O or Ca

$800 p (3 orientations vs. f with 7 possible orientations) Smaller possible # of orientations p or f shaped orbital

$1200 K (require less E to remove outer e- b/c more n, more shielding, further from nucleus) Smaller ionization energy Na or K

$1600 n = 5 to n = 6 Smaller energy required to excite an e- from n = 2 to n = 3 or from n = 5 to n = 6

$2000 O 2- Smaller ionic radius N 3- or O 2-

$400 Pauli Exclusion Principle This tells us no 2 e- in the same atom have the same E (or the same set of quantum numbers)

$800 Aufbau Principle This tells us that e- fill orbitals in increasing order of energy

$1200 Hund’s Rule This tells us the lowest energy is attained when # of e- with the same spin is maximized

$1600 Cr This element is an exception to the rule as it attains greater stability with a ½ filled d subshell and ½ filled s subshell than with its expected 4s 2 3d 4 configuration

$2000 Emission spectra / line spectra Rule: We can use this type of spectra to identify an element because no two will be the same

$400 More protons, greater nuclear charge This explains why atomic size decreases as we move from left to right across a period

$800 More n, greater shielding effect, larger n further away from nucleus This explains why ionic radius increases as we move down a group

$1200 Electronegativity This trend tells us an element’s ability to attract e-

$1600 Ionization Energy/ Potential This trend tells us the amount of energy required to remove an e- from an atom

$2000 Bottom Left This corner of the periodic table includes elements that exhibit the greatest metallic characteristics

$400 ns 2 np 6 The general e- config. for a noble gas

$800 ns 2 np 2 The general e- config. for an element in Group 4A

$1200 [Ne] The noble gas configuration of F - ion

$1600 Alkali earth metals An element with the general configuration ns 2 is part of which group (specific name please)

$2000 Actinoids An element with the configuration [Rn]7s 2 5f 12 is found in this series of elements

$400 l Tells us the shape of an orbital

$800 n Describes the energy level or size of an orbital

$1200 msms Tells us the spin of an e-

$1600 mlml Tells us orientation in space of a given orbital

$ , -2, -1, 0, 1, 2, 3 These are the possible values for m l when l = 3

$400 2 Maximum # of e- per orbital

$800 8 (2 in the s orbital + 6 in the p orbitals) Maximum # of e- in n = 2

$ # of d orbital orientations

$ (s, p, d, and f) Possible # of subshells in n = 4

$ (2 in 1s + 2 in 2s + 2 in 3s + 2 in 4s) # of e- in the s orbitals of a Ca atom

Daily Double Yes 2 0 +½

Daily Double n = 5 to n = 6 Energy required to excite an e- from n = 2 to n = 3 or from n = 5 to n = 6

Daily Double More n, greater shielding effect, larger n further away from nucleus This explains why ionic radius increases as we move down a group

The Jeopardy champion!