Evaluate Expressions Introduction 3a ……. 6b 6a - b 3b - 12 4t – 3z 5s – 2t 100 – 3d 36 d + 1 b = √( a² - c² ) ab.

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Presentation transcript:

Evaluate Expressions Introduction 3a ……. 6b 6a - b 3b t – 3z 5s – 2t 100 – 3d 36 d + 1 b = √( a² - c² ) ab

Formula …. Force F = ma The above formula is use in Physics to work out the force F required to move a ball of mass m at a given rate of acceleration a To work out F You need to know ma and F is the subject ….. What you want to work out After the = is the Math code.. ma.. you interpret to get an answer for F

Formulae … Force, Mass and Acceleration 7 3 x m = 7 a = 3 ma F = m a x 21 F = The RHS of the formula is interpreted then the letters are replaced by numbers

F = ma C. ÷ x 0 + On ² - Ans = √ (-) m = 6 a = 7 = = Next F = ma

Formula v=u + at The above formula is use in Physics to work out the final speed v of an object when you know what speed the object starts at, the rate at which it is accelerating and how long it travelled. To work out v You need to know ua t and V is the subject ….. What you want to work out After the = is the Math code.. U + at.. You interpret to get an answer for v

34 7 v = u + at u = 7 a = 4 t = 3 v = v =19 v = u + at + axt x BoDMas Multiply before Add

v = u + at u = 2 a = 4 t = C. ÷ x 0 + ² - Ans = √ (-) On v = x 9 v = v = u + at Start Next

V = u + at Five Questions u=6; a=7; t=6 For the given values of u, a and t calculate v using the formula v = u + at v = u + at = u=3; a=9; t=6 u=6; a=5; t=6 u=6; a=6; t=5 u=4; a=4; t= x x x x x C. ÷x 0 + On ² - Ans = √ (-) Start Next = = = = =

What First a = 6 32 A= 4a - A= - BoDMasMultiplication before subtraction C. ÷ x 0 + On ² - Ans = √ (-) Next Line …. BoDMas Expand Next A= 32 -

Fahrenheit temperatures into Celsius C 5F – = C = C 45 9 = C 45 ÷ 9 = C 5 = Ans+20 C. ÷ x On ² - Ans = √ (-) Find C when F= 41 Start Next

Fahrenheit To Centigrade u=4; a=4; t=6 Use the formula to convert Fahrenheit to Centigrade C = u=9; a=6; t=9 u=8; a=5; t=9 u=3; a=8; t=4 u=4; a=6; t= C. ÷x 0 + On ² - Ans = √ (-) Start Next = = = = =

Falling Ball s=½at² The thread holding a ball is cut. A stroboscope is used to picture the ball falling. The ball gets quicker ( accelerates ) as it falls. As the stroboscope flashes every second the numbers indicate how far it falls. The formula s=½at² can be used to calculate the distance that it falls. a = 10 t = 4 ½at² Ans÷2 C. ÷x 80 + On ² - Ans = √ (-) ½x x 4 x 4 ÷ 2 s= a= 10 Start Next

Evaluate 100 – a² p = 7 60 = = p² - = - BoDMasMultiplication before subtraction C. ÷ x 0 + On ² - Ans = √ (-) Next Line …. BoDMas Expand Next

Multiple of a Square C. ÷ x 0 + On ² - Ans = √ (-) f = 3 3f² = = Next x

Evaluate 100 – a 3 j = 3 33 = = j³ - = - BoDMasMultiplication before subtraction C. ÷ x 0 + On ² - Ans = √ (-) Next Line …. BoDMas Expand Next

Evaluate c³+c² m = 7 7x7 m² = = 7x7x7 m³ + = + BoDMasMultiplication before subtraction C. ÷ x 0 + On ² - Ans = √ (-) Next Line …. BoDMas Expand Next

5 Evaluate 36 / ( d + 1 ) d = 5 36 d + 1 = Two “sums”. One at the top and one at the bottom d+ 1 = 6 = 6 ÷ = 6

13 √( a² - c² ) a = 13 a²a² c = 5 - √( c²c² ) = √( a x a c x c ) Brackets first Show what a² and c² mean B o DM as Multiplication before subtraction = √( ) 144 = √( ) = 12

3d d ² d x d 3 x = = 48 d = 4

Of Type( 4c)² C. ÷ x 0 + On ² - Ans = √ (-) f = 3 (2f)² = = Next () ² x =