7.2* Natural Logarithmic Function In this section, we will learn about: The natural logarithmic function and its derivatives. INVERSE FUNCTIONS
If x and y are positive numbers and r is a rational number, then: LAWS OF LOGARITHMS Laws 3
Expand the expression Using Laws 1, 2, and 3, we get: LAWS OF LOGARITHMS
Express l n a + ½ l n b as a single logarithm. Using Laws 3 and 1 of logarithms, we have: LAWS OF LOGARITHMS Example 3
Differentiate y = l n(x 3 + 1). To use the Chain Rule, we let u = x Then, y = l n u. Thus, NATURAL LOG. FUNCTION Example 5
In general, if we combine Formula 2 with the Chain Rule as in Example 5, we get: NATURAL LOG. FUNCTION Formula 6
Find: Using Formula 6, we have: NATURAL LOG. FUNCTION Example 6
Differentiate: This time, the logarithm is the inner function. So, the Chain Rule gives: NATURAL LOG. FUNCTION Example 7
Find: NATURAL LOG. FUNCTION E. g. 8—Solution 1
If we first simplify the given function using the laws of logarithms, the differentiation becomes easier: This answer can be left as written. However, if we used a common denominator, we would see it gives the same answer as in Solution 1. NATURAL LOG. FUNCTION E. g. 8—Solution 2
Differentiate: We take logarithms of both sides and use the Laws of Logarithms to simplify: LOGARITHMIC DIFFERENTIATION Example 14
Differentiating implicitly with respect to x gives: Solving for dy/dx, we get: LOGARITHMIC DIFFERENTIATION Example 14
Since we have an explicit expression for y, we can substitute and write: LOGARITHMIC DIFFERENTIATION Example 14
If we hadn’t used logarithmic differentiation in Example 14, we would have had to use both the Quotient Rule and the Product Rule. The resulting calculation would have been horrendous. LOGARITHMIC DIFFERENTIATION Note
1.Take natural logarithms of both sides of an equation y = f(x) and use the Laws of Logarithms to simplify. 2.Differentiate implicitly with respect to x. 3.Solve the resulting equation for y’. STEPS IN LOGARITHMIC DIFFERENTIATION