6.5 Factoring Quadratics with Prime Leading Coefficients Objective: Be able to factor quadratics that start with a prime number.

Slides:



Advertisements
Similar presentations
Solving Quadratic Equations by Factoring. Remember: When solving a quadratic equation by factoring, you must first start with an equation set equal to.
Advertisements

4.2 Factors and Prime Factorization
1 Copyright © 2012, 2008, 2004 Pearson Education, Inc. Objectives Factoring Trinomials Factor trinomials when the coefficient of the quadratic term.
Factors and Greatest Common Factors
1 7.5 Factoring Trinomials CORD Math Mrs. Spitz Fall 2006.
7-3 Factoring x2 + bx + c Warm Up Lesson Presentation Lesson Quiz
P.4 FACTORING (التحليل) Objectives: Greatest Common Factor
6.2 Factoring Simple Quadratics Objective: Learn/review the basics needed for factoring.
Multiply. (x+3)(x+2) x x + x x Bellringer part two FOIL = x 2 + 2x + 3x + 6 = x 2 + 5x + 6.
Section 5.4 Factoring FACTORING Greatest Common Factor,
Objective 1.Factor quadratic trinomials of the form x2 + bx + c.
Algebra I Notes Section 9.5 (A) Factoring x 2 + bx + c With Leading Coefficient = 1 To factor a quadratic expression means to write it as a product of.
Do Now: Factor x2 – 196 4x2 + 38x x2 – 36 (x + 14)(x – 14)
Example Solution Think of FOIL in reverse. (x + )(x + ) We need 2 constant terms that have a product of 12 and a sum of 7. We list some pairs of numbers.
Factoring Trinomials. Recall by using the FOIL method that F O I L (x + 2)(x + 4) = x 2 + 4x + 2x + 8 = x 2 + 6x + 8 To factor x 2 + bx + c into (x +
1 Copyright © 2012, 2009, 2005, 2002 Pearson Education, Inc. 1.Obtain the grouping number ac. 2.Find the two numbers whose product is the grouping number.
Algebra I Notes Section 9.6 (A) Factoring ax 2 + bx + c With Leading Coefficient ≠ 1.
Objective The student will be able to: factor quadratic trinomials. Trial and Error Method SOL: A.2c Designed by Skip Tyler, Varina High School.
Unit 8, Lesson 7a. (x+3)(x+2) Multiplying Binomials (FOIL) FOIL = x 2 + 2x + 3x + 6 = x 2 + 5x + 6.
CLASSIFYING POLYNOMIALS. A _______________ is a sum or difference of terms. Polynomials have special names based on their _______ and the number of _______.
Slide Copyright © 2009 Pearson Education, Inc. 6.9 Solving Quadratic Equations by Using Factoring and by Using the Quadratic Formula.
Factoring Polynomials Section 2.4 Standards Addressed: A , A , CC.2.2.HS.D.1, CC.2.2.HS.D.2, CC.2.2.HS.D.5.
Find common and binomial factors by using a table.
Chapter 5 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 5-1 Factoring.
Chapter 5 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 5-1 Factoring.
Holt McDougal Algebra 1 Factoring x 2 + bx + c Holt Algebra 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Lesson Quiz Lesson Quiz Holt McDougal.
Factoring – Day 4 Factoring Trinomials Objective: To factor trinomials whose quadratic coefficient is 1.
4.4B Factoring Quadratics: Leading Coefficient ≠ 1 : Pattern (ac) Divide out a common monomial if possible. Multiply (a)(c) Use the “X” to find factors.
Factoring Factoring in the format ax2+bx+c Problem 1 X 2 + 7x + 10.
2.5 – Factoring Quadratics Special Cases. Special Case #1: Perfect Squares You can recognize this case because the coefficient of x and the constant are.
Holt McDougal Algebra 1 Factoring x 2 + bx + c Factor quadratic trinomials of the form x 2 + bx + c. Objective.
Factoring Quadratics Using the “X” method. Warm - up 1. (x - 7) 2 = x x (2k + 3) 2 = 4k k ( t - 6 )( t + 6 ) = t
6.6 Factoring Quadratics with Composite Leading Coefficients Objective: Be able to factor quadratics that start with a composite number.
Holt McDougal Algebra Factoring x 2 + bx + c Factor quadratic trinomials of the form x 2 + bx + c. Objective multiply two binomials using the Distributive.
Copyright © 2014, 2010, and 2006 Pearson Education, Inc. Chapter 5 Polynomials and Factoring.
Factoring Quadratic Trinomials a = 1 Chapter 10.5.
EVEN NUMBERS EVEN NUMBERS 1 = prime 2 = prime1 3 = prime 4 = 2 x 22 5 = prime 6 = 2 x 33 7 = prime 8 = 2 x 2 x 24 9 = 3 x 3 10 = 2 x 55.
Factoring Trinomials.
Solution Think of FOIL in reverse. (x + )(x + )
Factor a quadratic expression
2.6 Factoring Simple Quadratics
Chapter 6 Section 2.
9-15 Do Now Ed is a baseball player who gets a hit 6 times out of every 20 times at bat. How many hits will Ed expect to get if he is at bat 200 times?
Factoring.
Lesson Objective: I will be able to …
Factoring Pattern for x2 + bx + c, c positive
Solving Quadratic Equations
Factor into pairs like in “T” Find the pair whose sum is “b”
Factor into pairs like in “T” Find the pair whose sum is “b”
Factoring Trinomials.
7-3 Factoring x2 + bx + c Warm Up Lesson Presentation Lesson Quiz
Factoring Trinomials.
Algebra 1 Section 10.3.
Factoring Trinomials.
Chapter 6 Section 2.
Factoring ax2 + bx + c CA 11.0.
3.6-A Factoring Trinomials
Factoring using the “T” Method Trinomials in the form of x2 + bx + c
Factoring Pattern x2 + bc + c, c negative
Factoring Trinomials of the form ax2 + bx + c
Factoring Trinomials.
Factoring Trinomials.
Objective: Solve quadratics by factoring.
6.2 Factoring Simple Quadratics
6.5 Factoring Quadratics with Prime Leading Coefficients
How to Solve Equations using Factoring
M3D11 Have out: Bellwork: x – 4 x2 + 4x + 42 x + 2y x2 – 2xy + (2y)2
There is a pattern for factoring trinomials of this form, when c
Factoring Trinomials a = 1
U7D7 Have out: Bellwork: x – 4 x2 + 4x + 42 x + 2y x2 – 2xy + (2y)2
Presentation transcript:

6.5 Factoring Quadratics with Prime Leading Coefficients Objective: Be able to factor quadratics that start with a prime number.

Example 1 Factor this quadratic: 3x x + 10 Step one: 3 10 = 30 Step two: Find a factor pair of 30 whose sum is 11.

Example 1 Factor this quadratic: 3x x

Example 1 Factor this quadratic: 3x x + 10 Step three: Template (3x)(x)

Example 1 Factor this quadratic: 3x x + 10 Step four: (3x)(x) Choose values that create the 5 and 6 from step

Example 1 Factor this quadratic: 3x x + 10 Step five FOIL to check your work: (3x)(x) 3x 2 + 6x + 5x +10 3x 2 +11x

Example 2 Factor this quadratic: 5x x – 18 Step one: = -90 Step two: Find a factor pair of -90 whose sum is 27.

Example 2 Factor this quadratic: 5x x – There are more pairs here, but I stopped when I found the one I needed.

Example 2 Factor this quadratic: 5x x – 18 Step three: Template (5x)(x)

Example 2 Factor this quadratic: 5x x – 18 Step four: (5x)(x) Choose values that create the -3 and 30 from step 2. – 3+ 6

Example 2 Factor this quadratic: 5x x – 18 Step five FOIL to check your work: (5x)(x) 5x x – 3x – 18 5x 2 +27x – 18 – 3+ 6

Assignment 6.5 Worksheet