Acids and Bases. Drill – 4/23/08 Write everything you know about acids and bases!

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Presentation transcript:

Acids and Bases

Drill – 4/23/08 Write everything you know about acids and bases!

Drill – 4/30/08 Write the equation for the neutralization reaction between carbonic acid and calcium hydroxide.

ChemicalPredictionLitmus paper r  bLitmus paper b  rpH Vinegar Lemon Juice Windex Shampoo Conditioner Clear soda KOH Distilled Water Baking Soda solution HCl HNO3 Salt Water Oil Sugar water Drain cleaner Tilex Gatorade Hand soap Ammonia

Properties of Acids (in aq solution) 1.Sour taste 2.Low pH 3.Turn litmus paper red 4.Conduct electrical current

Properties of Bases (in aq solution) 1.Bitter taste 2.Slippery 3.High pH 4.Turn litmus paper blue 5.Conduct electrical current

Arrhenius Definition Acid = substance that releases H + ions in aq solution HCl  H + + Cl - Base = substance that releases OH - ions in aq solution NaOH  Na + + OH -

Bronsted-Lowry Definition As more and more substances were determined to have acidic or basic properties, even some without obvious H + or OH -, a new definition was needed. Acid = proton donor Base = proton acceptor

Bronsted-Lowry Definition Acid = proton donor H 2 O + HCl  H 3 O +1 + Cl -1

Bronsted-Lowry Definition Base = proton acceptor NH 3 + H 2 O  NH OH –

Acid-Base Reactions Known as a neutralization reaction. Acids and bases will react with each other to form water and salt. HCl + NaOH  H 2 O + NaCl

Day 2

Acid Naming Overview Binary Start with hydro- Element End with –ic acid Tertiary “I ate something, and now I am sick” If anion ends in –ate then the acid ends in – ic If the anion ends in –ite then the acid ends in -ous

Acids & Bases Review Acid –substance that releases H + ions in aq solution –Proton donor –Electron pair acceptor Base –substance that releases OH - ions in aq solution –Proton acceptor –Electron pair donator

Acid Strength A stronger acid will transfer MORE protons (H + ) than a weak acid. It will create more hydronium ions (H ) in water. Hydrochloric acid HCl + H 2 0  H Cl - Acetic Acid CH 3 COOH + H 2 0  H CH 3 COO - More dissociation! Less dissociation!

How do we compare the strength of an acid or a base? We measure the amount of hydronium ions they create (acids) or the amount of hydroxide ions they create (bases)….using concentration.

What is concentration? Using molarity, it is a measure of moles of solute in liters of solution. Concentration is measured in WATER!

H 2 O is both an acid and a base Water is simultaneously donating and accepting protons!

What are the ion concentrations in water? The concentrations of H 3 O + and OH - in pure water are each 1.0x10 -7 mol/L at 25ºC. Putting a symbol in brackets is used to signify the concentration. [H ] = 1.0x10 -7 M [OH - ] = 1.0x10 -7 M

Ionization Constant of water, K W K W = [H ] [OH - ] K W = (1.0x10 -7 )(1.0x10 -7 ) = 1.0x10 -14

Acids increase the [H ] Whenever [H ] is greater than [OH-], the solution is acidic. Bases increase the [OH-] Whenever [OH-] is greater than [H ], the solution is basic. With an increase in [H ], some of the H ions will react with the OH - ions, reducing [OH - ]. [H ][OH - ] will still = 1.0x10 -14

Concentration values tend to be small…so we use a more convenient scale. pH!

pH + pOH = 14 pH – A measure of the acidity of a solution. It is the negative logarithm of the hydronium ion [H ] concentration. pH = -log [ H ]

pH + pOH = 14 pOH – A measure of how basic a solution is. It is the negative logarithm of the hydroxide [OH - ] concentration. pOH = -log [OH - ]

The logarithm base 10 of a number x is the power to which 10 must be raised in order to equal x. Log 10 x = ?Log 100 = ? 10 ? = x10 ? = 100

Remember, our concentrations are SMALL. So we are going to be dealing with decimals… Log 10 x = ?Log.001 = ? 10 ? = x10 ? =.001

[H + ] = 1.00 x = pH = -log [H + ] pH = -log (1.00 x ) pH = 3 To determine pH from a concentration where 1 is the only digit, write the concentration in scientific notation. The exponent will be the pH.

For a base, you do the same thing except remember that you are solving for pOH first…

Solutions[H + ]pH[OH - ]pOH 1.0x10 -3 M HClO M HCl M HBr 1.0 x KOH 0.10 M NaOH H 2 SO 4