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Published byGyles Gaines Modified over 9 years ago
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11/25/15Oregon State University PH 211, Class #261 A compressed spring (k = 1.00 kN/m) is used to launch a block vertically to a height of 12.0 m above its launch position (the block is not attached to the spring— merely resting on it). The same block is launched again, but this time the spring is compressed half as much as the first time. What height (again, above its launch position) does the block reach this time? 1.1.44 m 2.3.00 m 3.3.60 m 4.6.00 m 5.None of the above.
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11/25/15Oregon State University PH 211, Class #262 a.A 10 N block is sitting at rest on a weightless platform supported by a spring whose constant is 25 N/m. What vertical distance is the spring compressed? b.What work would you do on the block simply by holding it in your hand and lowering it slowly by that same vertical distance? 1.(a) 2.50 m(b) –16.0 J 2.(a) 0.40 m(b) 4.0 J 3.(a) 0.40 m(b) – 4.0 J 4.(a) 0.25 m(b) – 1.6 J 5.None of the above.
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11/25/15Oregon State University PH 211, Class #263 Q:Continuing with the same setup from the previous question, suppose the 10 N block is simply placed on the spring’s platform and released. How would you calculate how much the spring compresses then? What’s the difference between this and case a above (where the block was sitting at rest on the platform)?
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11/25/15Oregon State University PH 211, Class #264 An ideal spring-mass system (k = 35 N/m; m = 2.0 kg) is oscillating horizontally on a frictionless surface. At the moment when the spring is compressed by 0.40 m, the system’s total mechanical energy is 1/3 kinetic and 2/3 potential. Find the mass’s maximum speed.
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