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Projectile motion is a form of two- dimensional motion in which a “projectile” is under the influence of gravity. Projectile motion is a form of two- dimensional motion in which a “projectile” is under the influence of gravity. There is motion in both the horizontal plane (x-axis) and the vertical plane (y-axis). What is projectile motion?
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What is a projectile? Projectiles are objects that are launched into the air. Projectiles are objects that are launched into the air. Ex. balls, arrows, long jumpers Ex. balls, arrows, long jumpers
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Projectile motion The path in which a projectile travels is a parabolic curve (assuming there is no wind resistance). The path in which a projectile travels is a parabolic curve (assuming there is no wind resistance).
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Projectiles vs. Free Falling Objects Projectiles fall at the same rate as free falling objects.
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Solving for projectile motion Since projectiles travel in both the horizontal and vertical planes, we can solve for the X and Y components. Since projectiles travel in both the horizontal and vertical planes, we can solve for the X and Y components. We can use the one-dimensional motion equations to solve for variables involved in two-dimensional motion problems. We can use the one-dimensional motion equations to solve for variables involved in two-dimensional motion problems.
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Projectile Motion x-Motion y-motion x-Motion y-motion V avg =Δx/Δt Δy = ½ (v i + v f ) Δt V avg =Δx/Δt Δy = ½ (v i + v f ) Δt g = (v f - v i ) / Δt g = (v f - v i ) / Δt Δy = v i Δt + ½ gΔt² Δy = v i Δt + ½ gΔt² v f ² = v i ² + 2gΔy v f ² = v i ² + 2gΔy The same equations we used in 1-D motion! The trick is to solve for “x” and “y” motion of 2-D moving objects independently!
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Projectile Motion Two types of projectile motion situations: Two types of projectile motion situations: 1. Horizontally launched projectiles 1. Horizontally launched projectiles 2. Projectiles launched at an angle 2. Projectiles launched at an angle
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Horizontal Projectile Motion Physics Book What am I going to do about book checks??? A VERY TALL BUILDING CRASH !!! x -y
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Sample Problem The Royal Bridge in Colarado is 321 m above the Arkansas River. If you kick a rock horizontally off the bridge and it hits the water with a horizontal displacement of 45 m, what is the velocity at which the rock was kicked? Δ y = -321 m g = -9.81 m/s² ΔxΔx Δ x = 45.0 m Δ y = ½(g)( Δ t)² √2(Δ y)/g = Δ t 8.10 s = Δ t Δ x = (V x,i )( Δ t) Δ x/ Δ t = V x,i 5.56 m/s = V x,i
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