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Published byBernard Adams Modified over 9 years ago
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Chapter 7
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Vertical (y) Horizontal (x) When solving a projectile problem, you can’t mix vertical and horizontal information in the same formula
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A projectile launched horizontally (would this be the x or y direction?) has no initial vertical motion. This means v 0y = 0 m/s Gravity/acceleration for falling objects (on Earth) is still -9.8 m/s 2 Starting distances and times are still 0
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A stone is thrown horizontally at a speed of 5.0 m/s from the top of a cliff 78.4 m high. a. How long does it take the stone to reach the bottom of the cliff? b. How far from the base of the cliff does the stone hit the ground?
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Draw a picture and label known information Think of the problems as consisting of 2 parts; horizontal and vertical Vertical motion is just like free-fall (gravity is acceleration) Horizontal motion is just like the chapter 5 problems The time from launch to hitting the ground is the same for both horizontal and vertical motion. You only solve for time once!
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Draw and label
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Group your information – either horizontal or vertical (x or y)
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If you don’t have time, solve for it. Remember, time can be used for both horizontal or vertical motion. Which formula should you use?
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d = d 0 + v 0 t + ½ at 2 78.4 = ½ (-9.8)t 2 t 2 = 16 t = ?
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Which formula?
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d = d 0 + vt d = 0 + 5(4) d = ?
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20 m
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