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HKDSE MATHEMATICS Ronald Hui Tak Sun Secondary School
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HOMEWORK SHW6-01, 6-A1 Almost all returned. Good job! SHW6-B1, 6-C1 Deadline: 18 Jan 2016 (Monday) SHW6-R1, 6-P1 Deadline: 25 Jan 2016 (Monday) No more delay please 22 October 2015 Ronald HUI
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Book 5A Chapter 6 Practical 3-dimensional Problems
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In 3-dimensional space, can we use angle of elevation, angle of depression and bearing to describe the relative positions of points?
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Yes, we can. N V A BO 45 30 E the angle of elevation of V from A is 30 , the angle of depression of B from V is 45 . For example,
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N V A BO 45 30 E N A B O 60 E V 30 U Besides, we can also find the bearings of U and V from O in the figure. the compass bearing of A from O is N30 E, the compass bearing of B from O is S60 E. One more example,
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H O horizontal ground In the figure, O is the point on a horizontal ground and H is a point above the ground. If K is the projection of H on the horizontal ground and the bearing of K from O is N E, then K N X The bearing of H from O is represented by the bearing of K from O, i.e. N E. E
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In the figure, A, B and C are three points on the horizontal ground. TA is a vertical tower. Then, the true bearing of T from C is ________. N N N 18 65 T A C B the compass bearing of T from B is _________, N65 W 072 90 – 18 = 72
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In the figure, TA is a vertical building of height 30 m. A, B and C are three points on the horizontal ground such that BC = 45 m and ∠ TCA = 40 . C is due west of A and B is due south of A. Find the compass bearing of C from B, correct to 3 significant figures. N T A E B C 40 30 m 45 m Consider △ ACT. tan TCA AC TA AC 30 m tan 40 AC 30 tan 40 m Consider △ ABC. sin ABC BC AC ABC 52.6 (cor. to 3 sig. fig.) 45 m 30 tan 40 m ∴ The compass bearing of C from B is N52.6 W.
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Follow-up question N 93 m T A 200 m B C 55 70 E In the figure, TC is a vertical building of height 200 m. A, B and C are three points on the horizontal ground. The angle of elevation of T from A is 55 . The compass bearings of A and B from T are N70 E and S80 E respectively. If BC = 93 m, find the distance between A and B, correct to 3 significant figures. Consider △ ACT. tan CAT AC TC AC 200 m tan 55 80 ACB = 180 70 80 adj. ∠ s on st. line = 30 AC 200 tan 55 m
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N 93 m T A 200 m B C 55 70 E 80 Consider △ ABC. AB 2 = AC 2 + BC 2 – 2(AC)(BC)cos ACB ∴ The distance between A and B is 75.5 m. AC 200 tan 55 m ACB = 30
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