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Warm Up - 2/15 on page 50  What is kept constant in Boyle’s Law?  Solve for the unknown:  P 1 = 0.456 atm  V 1 = 289 mL  P 2 = 0.287 atm  V 2 = ???

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Presentation on theme: "Warm Up - 2/15 on page 50  What is kept constant in Boyle’s Law?  Solve for the unknown:  P 1 = 0.456 atm  V 1 = 289 mL  P 2 = 0.287 atm  V 2 = ???"— Presentation transcript:

1 Warm Up - 2/15 on page 50  What is kept constant in Boyle’s Law?  Solve for the unknown:  P 1 = 0.456 atm  V 1 = 289 mL  P 2 = 0.287 atm  V 2 = ???

2 Gay-Lussac ’ s Law

3  Created by Joseph Gay-Lussac  Deals with changes in pressure and temperature (volume kept constant)  As one increases, the other increases as well (direct relationship)

4 Formula  P 1 = P 2  T 1 T 2

5 Example  At 120°C, the pressure of a sample of nitrogen is 1.07 atm. What will the pressure be at 205°C?  P 1 = 1.07 atm  T 1 = 120°C  P 2 = ???  T 2 = 205°C

6 Example  (1.07 atm) = P 2  (120°C) (205°C)  (1.07 atm)*(205°C) = P 2  (120°C)  P 2 = 1.80 atm

7 Charles ’ Law

8  Created by Jacques Charles  Deals with changes in volume and temperature (pressure kept constant)  As one increases, the other increases as well (direct relationship)

9 Formula  V 1 = V 2  T 1 T 2

10 Example  A gas at 65°C occupies 4.22 L. At what Celsius temperature will the volume be 3.87 L?  V 1 = 4.22 L  T 1 = 65°C  V 2 = 3.87 L  T 2 = ???

11 Example  (4.22 L) = (3.87 L)  (65°C) T 2  (4.22 L)*T 2 = (3.87 L)*(65°C)  T 2 = (3.87 L)*(65°C) = 59.6°C  (4.22 L)


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