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NET 221D : COMPUTER NETWORKS FUNDAMENTALS LECTURE 4: DATA LINK LAYER Behrouz A. Forouzan” Data communications and Networking 1.

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Presentation on theme: "NET 221D : COMPUTER NETWORKS FUNDAMENTALS LECTURE 4: DATA LINK LAYER Behrouz A. Forouzan” Data communications and Networking 1."— Presentation transcript:

1 NET 221D : COMPUTER NETWORKS FUNDAMENTALS LECTURE 4: DATA LINK LAYER Behrouz A. Forouzan” Data communications and Networking 1

2 Functions of the Data Link Layer The data link layer uses the services of the physical layer to send and receive bits over communication channels. It has a number of functions, including: 1. Addressing ( MAC / physical address) 2. Framing 3. Flow control (Regulating the flow of data so that slow receivers are not swamped ) 4. Error control (Dealing with transmission errors ) 5. Media access control. 2 Computer networks / Andrew S. Tanenbaum-- 5th ed

3 Cont. 3 To accomplish these goals, the data link layer takes the packets it gets from the network layer and encapsulates them into frames for transmission. Each frame contains a frame header, a payload field for holding the packet, and a frame trailer Frame Header contains the physical address of the next receiving node Computer networks / Andrew S. Tanenbaum-- 5th ed

4 A ) Framing Behrouz A. Forouzan” Data communications and Networking 4  The data link layer needs to pack bits into frames, so that each frame is distinguishable from another. Example :  Our postal system practices a type of framing.  The simple act of inserting a letter into an envelope separates one piece of information from another; the envelope serves as the delimiter.

5 Cont. 5 A good design ( for Breaking up the bit stream into frames ) must make it easy for a receiver to find the start of new frames while using little of the channel bandwidth.  We will look at three methods:  Byte count.  Flag bytes with byte stuffing.  Flag bits with bit stuffing. Computer networks / Andrew S. Tanenbaum-- 5th ed

6 1. Byte count A character stream. (a) Without errors. (b) With one error. The first framing method uses a field in the header to specify the number of bytes in the frame. 6 Computer networks / Andrew S. Tanenbaum-- 5th ed

7 2. Flag bytes with byte stuffing  A flag byte, 8-bit flag, is inserted as both the starting and ending delimiter.  Two consecutive flag bytes indicate the end of one frame and the start of the next. 7 Computer networks / Andrew S. Tanenbaum-- 5th ed

8 Byte Stuffing 8  However, there is a still a problem we have to solve.  It may happen that the flag byte occurs in the data, especially when binary data such as photographs or songs are being transmitted.  One way to solve this problem is to have the sender’s data link layer insert a special escape byte (ESC) just before each ‘‘accidental’’ flag byte in the data.  The data link layer on the receiving end removes the escape bytes before giving the data to the network layer.  This technique is called byte stuffing. Computer networks / Andrew S. Tanenbaum-- 5th ed

9 3. Flag bits with bit stuffing.  Framing can be also be done at the bit level, so frames can contain an arbitrary number of bits made up of units of any size.  Each frame begins and ends with a special bit pattern, 01111110 or 0x7E in hexadecimal.  Whenever the sender’s data link layer encounters five consecutive 1s in the data, it automatically stuffs a 0 bit into the outgoing bit stream (bit stuffing)  When the receiver sees five consecutive incoming 1 bits, followed by a 0 bit, it automatically de-stuffs (i.e., deletes) the 0 bit. 9 Computer networks / Andrew S. Tanenbaum-- 5th ed

10 B) Error control 10  How to make sure all frames are eventually delivered to the network layer at the destination and in the proper order.  Assume for the moment that the receiver can tell whether a frame that it receives contains correct or faulty information (using error detection and correction techniques)  The usual way to ensure reliable delivery is to provide the sender with some feedback about what is happening at the other end of the line.  Typically, the protocol calls for the receiver to send back special control frames bearing positive or negative acknowledgements about the incoming frames. Computer networks / Andrew S. Tanenbaum-- 5th ed

11 Cont. 11  If the sender receives a positive acknowledgement about a frame, it knows the frame has arrived safely.  On the other hand, a negative acknowledgement means that something has gone wrong and the frame must be retransmitted again. Computer networks / Andrew S. Tanenbaum-- 5th ed

12 Error detection and correction Behrouz A. Forouzan” Data communications and Networking 12

13 10.13 Redundancy redundancy The central concept in detecting or correcting errors is redundancy. To be able to detect or correct errors, we need to send some extra bits with our data. These redundant bits are added by the sender and removed by the receiver. Their presence allows the receiver to detect or correct corrupted bits.

14 1. Parity Check Behrouz A. Forouzan” Data communications and Networking 14  The most common and least expensive.  It can be Simple or Two Dimensional. How does it work? A k-bit dataword is changed to an n-bit codeword where n = k + 1. The extra bit, called the parity bit, is selected to make the total number of 1s in the codeword even Note : there is either even parity or odd parity. Example: Assume the sender sends the dataword 1011. Since the number of 1's is odd then the parity bit is equal to 1 and the codeword for this dataword is 10111.

15 Behrouz A. Forouzan” Data communications and Networking 15  Simple parity check can detect all single-bit errors. It can detect burst errors only if the total number of errors in each data unit is odd.  A better approach is the two-dimensional parity check which organizes the data units into table (rows and columns). The parity bit for each column is Calculated and added to the table as a new row (column parity)

16 Two-dimensional parity check Behrouz A. Forouzan” Data communications and Networking 16

17 2. Cyclic Redundancy Check Behrouz A. Forouzan” Data communications and Networking 17  In a cyclic code, if a codeword is cyclically shifted (rotated), the result is another codeword.  Example: if 1011000 is a codeword and we cyclically left- shift, then 0110001 is also a codeword.

18 10.18 Figure 10.14: CRC encoder and decoder Behrouz A. Forouzan” Data communications and Networking 18

19 Table 10.6 : A CRC code with C(7, 4) Behrouz A. Forouzan” Data communications and Networking

20 The Process of CRC At the Sender: 1. The encoder, the dataword has k bits (4 here).The codeword has n bits ( 7). 2. The size of the dataword is augmented by adding n-k (3 here) 0s to the right-hand size of the word. 3. The generator uses a divisor of size n-k+1 (4 here), predefined and agreed upon. 4. The generator divides the augmented dataword by the divisor ( modulo-2 division). 5. The reminder is appended to the dataword to create the codeword. Behrouz A. Forouzan” Data communications and Networking

21 The Process of CRC At the Receiver: 1. The decoder does the same division process as the encoder. 2. The reminder of the division is the syndrome. If the syndrome is all 0s, there is no error, the dataword separated from the received codeword and accepted. Otherwise, everything is discarded. Behrouz A. Forouzan” Data communications and Networking

22 Figure 10.15: Division in CRC encoder Behrouz A. Forouzan” Data communications and Networking

23 Figure 10.16: Division in the CRC decoder for two cases Behrouz A. Forouzan” Data communications and Networking

24 3. CHECKSUM Behrouz A. Forouzan” Data communications and Networking 24  Checksum is an error-detecting technique that can be applied to a message of any length.  Like CRC, checksum based on the concept of redundancy.

25 Example 25 Suppose the message is a list of five 4-bit numbers that we want to send to a destination.  In addition to sending these numbers, we send the sum of the numbers.  For example, A sender wants to send the set of numbers (7, 11, 12, 0, 6) the process will be as follow:  Sum up the numbers = 7+11+12+0+6 = 36  Then convert the decimal number 36 in binary = (100100)2.  To change it to a 4-bit number ( as the sending numbers) we add the extra leftmost bit to the right four bits as shown below. This is called sum in one’s complement.

26 Example Cont. Behrouz A. Forouzan” Data communications and Networking 26  Then complements the result to get the checksum.  6= ( 0110) 2, the complement of 6 = 15 - 6 = 9 Or (1001) 2 = 9 = (1001 )2  The sender sends the five data numbers and the checksum (7, 11, 12, 0, 6, 9).  If there is no corruption in transmission, the receiver receives (7, 11, 12, 0, 6, 9) and adds them in one’s complement to get 15.

27 Figure 10.16: Example 10.24 100100 36 10 _________ 0110 6 1001 9 101101 45 10 _________ 1111 15 0000 0

28 C) Flow Control Behrouz A. Forouzan” Data communications and Networking 28  Another important design issue that occurs in the data link layer (and higher layers as well) is what to do with a sender that systematically wants to transmit frames faster than the receiver can accept them.  This situation can occur when the sender is running on a fast, powerful computer and the receiver is running on a slow, low-end machine.

29 Cont. 29  Two approaches are commonly used.  In the first one, feedback-based flow control, the receiver sends back information to the sender giving it permission to send more data, or at least telling the sender how the receiver is doing.  In the second one, rate-based flow control, the protocol has a built-in mechanism that limits the rate at which senders may transmit data, without using feedback from the receiver.  In this chapter we will study feedback-based flow control schemes, primarily because rate-based schemes are only seen as part of the transport layer

30 Flow control schemes Behrouz A. Forouzan” Data communications and Networking 30

31 NOISELESS CHANNELS Behrouz A. Forouzan” Data communications and Networking 31  Let us first assume we have an ideal channel in which no frames are lost, duplicated, or corrupted.  We introduce two protocols for this type of channel.  Simplest Protocol  Stop-and-Wait Protocol

32 Figure 11.6 The design of the simplest protocol with no flow or error control Behrouz A. Forouzan” Data communications and Networking

33 11.33 Algorithm 11.1 Sender-site algorithm for the simplest protocol Behrouz A. Forouzan” Data communications and Networking Algorithm 11.2 Receiver-site algorithm for the simplest protocol

34 Figure 11.7 Flow diagram for Example 11.1 Behrouz A. Forouzan” Data communications and Networking

35 Stop-and-Wait Protocol Figure 11.8 Design of Stop-and-Wait Protocol Sender sends one frame, until it receives confirmation from the receiver and then sends next frame

36 Figure 11.9 Flow diagram Behrouz A. Forouzan” Data communications and Networking

37 NOISY CHANNELS Behrouz A. Forouzan” Data communications and Networking 37  Although the Stop-and-Wait Protocol gives us an idea of how to add flow control to its predecessor, noiseless channels are nonexistent.  We discuss three protocols in this section that use error control.  Stop-and-Wait Automatic Repeat Request(ARQ)  Go-Back-N ARQ  Selective Repeat ARQ ) - any time an error is detected in an exchange, specified frames are retransmitted Automatic Repeat Request (ARQ ) - any time an error is detected in an exchange, specified frames are retransmitted

38 1. Stop-and-Wait ARQ Behrouz A. Forouzan” Data communications and Networking 38  Error correction in Stop-and-Wait ARQ is done by keeping a copy of the sent frame and retransmitting of the frame when the timer expires.  We use sequence numbers to number the frames.  The sequence numbers are based on modulo-2 arithmetic.  The acknowledgment number always announces in modulo-2 arithmetic the sequence number of the next frame expected.

39 Figure 11.10 Design of the Stop-and-Wait ARQ Protocol Behrouz A. Forouzan” Data communications and Networking

40 Figure 11.11 shows an example of Stop-and-Wait ARQ. Frame 0 is sent and acknowledged. Frame 1 is lost and resent after the time-out. The resent frame 1 is acknowledged and the timer stops. Frame 0 is sent and acknowledged, but the acknowledgment is lost. The sender has no idea if the frame or the acknowledgment is lost, so after the time-out, it resends frame 0, which is acknowledged. Example 11.3 Behrouz A. Forouzan” Data communications and Networking

41 Figure 11.11 Flow diagram for Example 11.3 Behrouz A. Forouzan” Data communications and Networking

42 2. Go-Back-N ARQ Behrouz A. Forouzan” Data communications and Networking 42  In the Go-Back-N Protocol, the sequence numbers are modulo 2 m, where m is the size of the sequence number field in bits.  Sliding window defines the range of sequence numbers that is the concern of the sender and receiver - sender and receiver deals with only a part of the range of sequence numbers  The send window is an abstract concept defining an imaginary box of size 2 m − 1 with three variables: Sf, Sn, and S size.  The send window can slide one or more slots when a valid acknowledgment arrives.

43 Cont. Behrouz A. Forouzan” Data communications and Networking 43  The receive window is an abstract concept defining an imaginary box of size 1 with one single variable R n.  The window slides when a correct frame has arrived; sliding occurs one slot at a time. ● ACKs are cumulative - more than one frame can be acknowledged by a single ACK

44 Figure 11.12 Send window for Go-Back-N ARQ Behrouz A. Forouzan” Data communications and Networking

45 Figure 11.13 Receive window for Go-Back-N ARQ Behrouz A. Forouzan” Data communications and Networking

46 Figure 11.14 Design of Go-Back-N ARQ Behrouz A. Forouzan” Data communications and Networking

47 Figure 11.15 Window size for Go-Back-N ARQ Behrouz A. Forouzan” Data communications and Networking

48 In Go-Back-N ARQ, the size of the send window must be less than 2 m ; the size of the receiver window is always 1. Note Behrouz A. Forouzan” Data communications and Networking

49 Figure 11.17 shows what happens when a frame is lost. Frames 0, 1, 2, and 3 are sent. However, frame 1 is lost. The receiver receives frames 2 and 3, but they are discarded because they are received out of order. The sender receives no acknowledgment about frames 1, 2, or 3. Its timer finally expires. The sender sends all outstanding frames (1, 2, and 3) because it does not know what is wrong. This means that when ACK 2 arrives, the sender is still busy with sending frame 3. Example 11.7 Behrouz A. Forouzan” Data communications and Networking

50 Figure 11.17 Flow diagram for Example 11.7 Behrouz A. Forouzan” Data communications and Networking

51 3. Selective Repeat ARQ 51  Go-Back-N ARQ simplifies the process at the receiver site.  The receiver keeps track of only one variable, and there is no need to buffer out-of-order frames; they are simply discarded.  However, this protocol is very inefficient for a noisy link. In a noisy link a frame has a higher probability of damage, which means the resending of multiple frames.  This resending uses up the bandwidth and slows down the transmission. For noisy links, there is another mechanism that does not resend N frames when just one frame is damaged; only the damaged frame is resent.  This mechanism is called Selective RepeatARQ. Computer networks / Andrew S. Tanenbaum-- 5th ed

52 Figure 11.18 Send window for Selective Repeat ARQ Figure 11.19 Receive window for Selective Repeat ARQ

53 Figure 11.20 Design of Selective Repeat ARQ Behrouz A. Forouzan” Data communications and Networking

54 This example is similar to Example 11.3 in which frame 1 is lost. We show how Selective Repeat behaves in this case. Figure 11.23 shows the situation. One main difference is the number of timers. Here, each frame sent or resent needs a timer, which means that the timers need to be numbered (0, 1, 2, and 3). The timer for frame 0 starts at the first request, but stops when the ACK for this frame arrives. The timer for frame 1 starts at the second request, restarts when a NAK arrives, and finally stops when the last ACK arrives. The other two timers start when the corresponding frames are sent and stop at the last arrival event. A NAK is sent once for each window position and defines the first slot in the window. In Selective Repeat, ACKs are sent when data are delivered to the network layer. If the data belonging to n frames are delivered in one shot, only one ACK is sent for all of them. Example 11.8 Behrouz A. Forouzan” Data communications and Networking

55 Figure 11.23 Flow diagram for Example 11.8 Behrouz A. Forouzan” Data communications and Networking

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