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Physics 12 Circuits 6 – Basic Complex Circuits Mr. Jean
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The plan: Complex Circuits How Circuits are graded
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Complex Circuits:
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Hint Ideas: Get the Circuits into groupings. Grouping depend on the way the different loads are acting on each other.
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Thus for this example: We have to first deal with the R2 & R3 group. This group is a parallel circuit. Then once this is complete we can move onto the next grouping. Let’s label R2 & R3 as group A.
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Now we can see that once we deal with group A (which is the parallel circuit) we can then work with the entire circuit. Since the rest of the circuit is a series circuit. So solve for equivalent resistance through group A (using the parallel circuit technique) and the we can attack this circuit like we would before.
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By solving the group A’s resistance we can now find the entire circuits equivalent resistance by applying the series formulas.
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Using Ohm’s law and the properties of circuits we can then find the current in the system.
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Once we have the current through the entire system we can then solve for the voltages across R1 & Group A.
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We can then look at the current through R2 and R3 of resistors. Again we use Ohm’s Law. V = IR
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Let’s make up a circuit: We have a “AA” battery with 1.5volts. Grant (R1) is holding the battery under water while holding two wires. On one wire we have a LED, on the other wire we have a very cheap heater and we have Davie with a SPST switch which is connected to the other end of the battery.
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Circuit Diagram: 2 Pts Circuit is properly drawn Circuit has labels
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Calculations for Amps: 5pts Correct formula for current Correct Calculation for current Correct resistance for Light Correct resistance for heater Correct units for each
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EQ Resistance: 3pts Correct formula Correct units Correct calculations
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Complex Circuit Create diagram Solve for current and voltage through each. Resistors R1, R2, R3 have the following resistance 2ohm, 6ohm, 12ohm and are connected to a 12 volt battery source. R1 & R2 are in parallel with each other but in series with R3. –Solve for the voltage drop and current through each.
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