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I.Definition A.Way to solve problems using the units, or dimensions, of a measurement.

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Presentation on theme: "I.Definition A.Way to solve problems using the units, or dimensions, of a measurement."— Presentation transcript:

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2 I.Definition A.Way to solve problems using the units, or dimensions, of a measurement

3 II.Conversion Factors A. Ratio of equivalent measurements B. Do not count when determining sig. figs. C. Written as fractions D. Reciprocals are also true

4 E.Examples i. 4 quarters = 1 dollar 4 quarters 1 dollar 4 quarters 1 yard 3 feet 1 yard ii.1 yd = 3 ft

5 III.Metric Conversion Factors PropertyBase UnitPrefixSymbolRelationship Lengthmeter (m) kilok1 km = 10 3 m centic1 cm = 10 −2 m millim1 mm = 10 −3 m nanon1 nm = 10 −9 m Mass kilogram (kg) kilok1 kg = 10 3 g millim1 mg = 10 −3 g VolumeLiter (L) millim1 mL = 10 −3 L micro μ 1 μ L = 10 −6 L ** l mL = 1 cm 3 (cubic centimeter or cc)

6 IV.Problem solving steps A.Identify the given B.Draw your table C.Identify what your trying to find D.Find and insert conversion factors (cancel as you go) E.Multiply across numerators F.Divide by the denominators (individually) G.Round answer to correct sig figs!

7 V.Examples A.How milligrams are in 750 grams.

8 B.How many kilograms are in 10.5 grams.

9 C.How many milligrams would a 0.75 lb. hamburger weigh? (1 lb = 453.6 g)

10 D.How many centimeters are there in 1.5 yards? (1 yd = 3 ft, 1 ft = 12 in, 1 in = 2.54 cm)

11 E.How many cubic centimeters (cc) are in 2.5 liters?


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