Download presentation
Presentation is loading. Please wait.
Published byAlban Stephens Modified over 8 years ago
1
Projectile Motion The motion of a falling object with air resistance and gravity acting on it
2
Projectiles A projectile is any object upon which the only force is gravity Projectiles travel with a parabolic trajectory due to gravity There are no horizontal forces and no horizontal acceleration on projectiles
3
Projectiles The horizontal velocity of a projectile is constant The vertical acceleration of a projectile is caused by gravity and is 9.8m/s/s down The horizontal and vertical motion of a projectile are independent of each other
4
Projectile Motion A force is not required to keep an object in motion A force is required to maintain acceleration If a projectile is moving upward there is a downward force and downward acceleration The object is moving upward and slowing down
5
Gravity and vertical acceleration Gravity only causes a vertical acceleration Gravity does not affect the horizontal distance or motion an object travels Gravity will affect the vertical distance and motion of an object only
6
Horizontally launched projectiles There has to be a horizontal force to cause a horizontal acceleration A projectile has a constant horizontal velocity and a downward vertical acceleration (deceleration)
7
Horizontal Projectiles Horizontal MotionVertical Motion ForcesNoYes, gravity AccelerationNoYes, gravity at 9.8m/s/s VelocityConstantChanging by 9.8m/s each second
8
Non-Horizontally Launched Projectiles When the projectile is launched at an angle the path is a parabola If there was no gravity the projectile would continue upward no gravity gravity
9
Vertical Displacement The vertical displacement of an object can be calculated using: y =.5 * g * t 2 (* = multiplied by) y = vertical displacement g = gravity at -9.8m/s/s t = time in seconds Use this equation when an object is dropped from rest – it has no initial vertical velocity
10
Horizontal Displacement The horizontal displacement of a projectile can be calculated using the following: x = v ix * t where x = horizontal displacement in m v ix = initial horizontal velocity in m/s t = time in s In this case there is no initial vertical velocity, since the projectile is launched horizontally
11
Vertical Displacement of an Angled- Launched Projectile To calculate the vertical displacement of a projectile launched at an angle y = v iy * t + 0.5 * g * t 2 y= vertical displacement in m v iy = initial velocity in m/s t = time in s g = gravity, -9.8 m/s/s t = time in s
12
Sample Problem A projectile has an initial velocity v iy of 19.6m/s and a horizontal velocity of 33.9m/s, what is the vertical and horizontal displacement after 1 s? y = v iy * t + 0.5 * g * t 2 y = (19.6m/s) x (1s) + 0.5 x (-9.8m/s/s) x (1s) 2 y = 19.6m/s + (-4.9m) y = 14.7m (vertical displacement) x = v ix * t x = (33.9m/s) x (1s) x = 33.9m (horizontal displacement)
Similar presentations
© 2024 SlidePlayer.com. Inc.
All rights reserved.