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Entrance Ticket Part I 2/12/15 We are still on e.t. 8 We are still on e.t. 8 1.) If you have a propane cylinder, what are two ways you could increase the.

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Presentation on theme: "Entrance Ticket Part I 2/12/15 We are still on e.t. 8 We are still on e.t. 8 1.) If you have a propane cylinder, what are two ways you could increase the."— Presentation transcript:

1 Entrance Ticket Part I 2/12/15 We are still on e.t. 8 We are still on e.t. 8 1.) If you have a propane cylinder, what are two ways you could increase the pressure inside the cylinder. pressure inside the cylinder. (use your knowledge of (use your knowledge of Kinetic Molecular Theory) Kinetic Molecular Theory) *Grades are posted!

2 Activity Use Chapter 14.1 to help you Get into two groups at each lab table (unless your table has less than 4). There are 10 statements in the manila envelope. Half are true, half are false. Use Chapter 14.1 to help you separate them.

3 Entrance Ticket Part II 2/12/15 Use Chapter 14.1 & 14.2 to help you  Describe the relationship between Pressure and Volume of gases.  Describe the relationship between Temperature and Volume of gases. Homework: Chapter 14.2 #15-21

4 Boyle’s Law! P 1 V 1 = P 2 V 2  A balloon has a Volume of 4.3L at a pressure of 1.2 atm. What is the volume at 3.6 atm?

5 Boyle’s Law! A balloon has a Volume of 4.3L at a pressure of 1.2 atm. What is the volume at 3.6 atm? P 1 V 1 = P 2 V 2 1.2 atm x 4.3L = 3.6 atm x V 2 1.2 atm x 4.3L = 3.6 atm x V 2 5.16 atm L = 3.6 atm x V 2 1.4 L = V 2

6 Boyle’s Law 2.A gas with a volume of 4.00L at a pressure of 205 kPa is allowed to expand to a volume of 12.0L. What is the pressure in the container if the temperature remains constant?

7 Boyle’s Law! P 1 V 1 = P 2 V 2 205 kPa x 4.00 L = P 2 x 12.0 L 205 kPa x 4.00 L = P 2 x 12.0 L 820 kPa L = P 2 x 12.0 L 68.3 kPa = P 2

8 Boyle’s Law 3. A gas at 101.3 kPa has a volume of 1.80 L. What is the pressure if the volume is reduced to 1.10 L?

9 Boyle’s Law! P 1 V 1 = P 2 V 2 101.3 kPa x 1.80 L = P 2 x 1.10 L 182 kPa L = P 2 x 1.10 L 166 kPa = P 2

10 Entrance Ticket 2/13/15 Please get out last night’s homework 1.) Assuming constant temperature, what is the volume of a balloon at 1.8 atm if its volume decreased to 8.2 L at a pressure of 2.0 atm? 2.) If you decrease the temperature of a gas, what happens to the volume of the gas? H.W. 14.2 # 9,10 (do this on the same paper as last night’s homework)

11 Entrance Ticket Answer P 1 V 1 = P 2 V 2 1.) 1.8 atm x V 1 = 2.0 atm x 8.2 L 1.8 atm x V 1 = 16.4 atm L V 1 = 9.1 L H.W. 14.2 # 9,10 (do this on the same paper as last night’s homework)

12 Charles’ Law A gas with a volume of 9.32 L at 280 K is cooled to 245 K, what is the new volume?

13 Charles’ Law Assuming constant pressure, what is the temperature of a gas whose volume at 32 ºC is 5.6 L, if its volume increases to 11.2 L?

14 Entrance Ticket 2/17/15 1.) Make a quick sketch of a Boyle’s law graph and a Charles’ law graph. Check your homework, answers: #9) 3.39 L #10) 8.36 L H.W. finish Boyle’s/Charles problems

15 Boyles/Charles Law problems -Show all work and units -Box your answers *If it is not completed entirely, you will not be allowed to turn it in

16 Make sure to box your answers on your Boyles/Charles Law problems. Pass it up ONLY if they are completed entirely*. *If it is not completed you will turn it in to the late work box when it is complete.

17 Combined Gas Law Put Boyle’s and Charles’ together! Remember, temp. needs to be in K!

18 Combined Gas Law What is the final volume of a gas that has an initial volume of 6.5 L at 250 K and 1.8 atm when the temperature is raised to 320 K and the pressure raised to 4.3 atm?

19 Combined Gas Law P 1 V 1 T 2 = P 2 V 2 T 1 1.8atm x 6.5L x 320K = 4.3atm x V 2 x 250K 3,744 atm L K = 1,075 atm K x V 2 V 2 = 3.5 L

20 Combined Gas Law Answers 1.) 0.62 atm 2.) 4.7 K 3.) 2.0 L 4.) 14,000 torr 6.) 3,000 kPa, The can will not burst

21 Popcorn Lab: PV = nRT Tear out pages 29-31. Be safe today! Post Lab #1) Only do #1 if you had un-popped kernels! #2) Remember: a percentage is the same thing as a fraction!!! A fraction is part divided by whole. The mass of your water is the part, the mass of your 30 kernels is the whole. After dividing, multiply by 100 to convert your fraction to a percentage!

22 Post Lab #1) Only do #1 if you had un-popped kernels! Use your answer to #1 for the mass of water in all 30 kernels. #2) Remember: a percentage is the same thing as a fraction! A fraction is part divided by whole. The mass of your water is the part, the mass of your 30 kernels is the whole. After dividing, multiply by 100 to convert your fraction to a percentage! ! Honors homework: Read 14.3 tonight!


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