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May 4, 2012 AGENDA: 1 – Bell Ringer & Part. Log 2 – Demo 3 – CN: Lussac’s Law 4 – Work Time Today’s Goal: Students will be able to calculate using Lussac’s.

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Presentation on theme: "May 4, 2012 AGENDA: 1 – Bell Ringer & Part. Log 2 – Demo 3 – CN: Lussac’s Law 4 – Work Time Today’s Goal: Students will be able to calculate using Lussac’s."— Presentation transcript:

1 May 4, 2012 AGENDA: 1 – Bell Ringer & Part. Log 2 – Demo 3 – CN: Lussac’s Law 4 – Work Time Today’s Goal: Students will be able to calculate using Lussac’s Law. Homework 1. Lussac’s Law and Mixed Practice HW – due 5/7/12 2. Work from Week 32 is due TODAY. 3. Make up QUIZ 16 by Monday.

2 http://www.youtube.com/watch?v =ZgTTUuJZAFs Demonstration of Charles’ Law

3  Topic: Lussac’s Law  Date: 5/4/2012  Lussac’s Law = For a given amount of gas at a constant volume, the PRESSURE of the gas is directly related to TEMPERATURE.  So if: T ↑ = P ↑ T ↓ = P ↓ T α P 1.Contrast 2.Describe 3.Explain Temperature Constant Volume Pressure

4  Topic: Lussac’s Law  Date: 5/4/2012  Temperature = Kelvin (K)  Remember to convert: K = ° C + 273  Pressure = (atm) 1.Contrast 2.Describe 3.Explain P 1 = P 2 T 1 T 2 P 1 T 2 = P 2 T 1

5  Topic: Lussac’s Law  Date: 5/4/2012  A refrigerated bottle of pop is at 4 ° C. The pressure of the bottle is 1atm. The bottle is then taken to the beach on a hot summer day, where it is 37 ° C. What is the new pressure of the bottle? 1.Contrast 2.Describe 3.Explain P 1 T 2 = P 2 T 1 (1)(310) = P 2 (277) 310 = P 2 (277) 277 P 2 = 310/277 P 2 = 1.12atm T 1 =4 ° C+273=277K P 1 =1.0atm T 2 =37 ° C+273=310K P 2 =? 1 st Predict: If T ↑ then P ↑.


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