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Published byJonah Campbell Modified over 8 years ago
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Work and Energy 功和能
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“It is important to realize that in physics today, we have no knowledge of what energy is.” Richard Feynman (1918 – 1988) Nobel prize winner
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“It is important to realize that in physics today, we have no knowledge of what energy is.” Richard Feynman (1918 – 1988) Nobel prize winner Read: “Surely You’re Joking, Mr Feynman!”
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We may not know what energy is, but we do know how to calculate it.
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System and surroundings System Surroundings
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The energy principle System Surroundings The change in energy of a system (E sys ) is equal to the work done by the surroundings (W surr ), and to other kinds of energy transfers between system and surroundings.
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The total energy of the universe is conserved. System
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Energy is transferred between system and surroundings. Never created, never destroyed. So for any choice of system:
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Energy of a single particle Units of energy: the joule (J). 1 J = 1 kg (m/s) 2.
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For a particle at rest, γ = 1. A particle not moving (v = 0) has energy proportional to its mass. Mass and energy are the same thing!
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Mass turning into energy.
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For a moving particle, γ > 1 E particle mc 2 K γmc 2 Total energy is the rest energy plus an extra amount, related to the particle’s motion.
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For a moving particle, γ > 1 Rest energy E particle mc 2 K γmc 2 Kinetic energy 动能
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Kinetic energy E particle mc 2 K γmc 2
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Kinetic energy at low speeds When v << c, we can use a binomial expansion to simplify the expression for kinetic energy:
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Kinetic energy at low speeds E particle mc 2 K γmc 2
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Kinetic energy at low speeds E particle mc 2 K γmc 2
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Work
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Change in momentum is related to impulse: force multiplied by time.
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What is related to force multiplied by distance?
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Change in energy. This quantity is called “work” ( 功 ).
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Impulse = Force x time Work = Force x distance …changes momentum …is a vector ( 矢量 ) …changes energy …is a scalar ( 标量 )
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Work done by a constant force Units of work: the joule (J). Work is energy.
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θ 1.0 m x y Example: How much work is done by the force F on the red block?
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Only the component of the force in the direction of motion does work.
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The vector dot product For any two vectors A and B: θ
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Work done by a constant force where
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Δx = +2 m F x = +3 N Is the work done on the block positive (+) or negative (-) ? The block is speeding up, so the work is positive.
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Δx = +2 m F x = -3 N Is the work done on the block positive (+) or negative (-) ? The block is slowing down, so the work is negative.
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Δx = -2 m F x = -3 N Is the work done on the block positive (+) or negative (-) ? The block is speeding up, so the work is positive.
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Δx = -2 m F x = -3 N Is the work done on the block positive (+) or negative (-) ? The block is slowing down, so the work is negative.
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Work done by a changing force
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