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Published byNicholas Horn Modified over 9 years ago
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Warm - Up Determine if (3,4) is a solution to the equation: 1.) y = 2x – 2 2.) 6x – 3y = 6 4 = 2(3) – 2 4 = 6 – 2 6(3) – 3(4) = 6 18 – 12 = 6 YES ? ? ? ?
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CA Standards: CA 6.0: Students graph linear equations and compute x,y intercepts. Objectives: (1) Students will graph equations using x-y charts and (2) find x and y intercepts. Agenda: 10/04/11 1.) Warm-up 2.) Questions WS Real Life Applications Linear Equations 3.) Lesson Graphing linear equations Using T-Charts ppt 4.) Class/Homework WS Graphing Linear Equations Using T-Tables 5.) Work with your Neighbor STAY ON TASK!!!
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Linear Equations A linear equation means that the graph is a straight line. Linear Equations: Variables have first power only No products of two variables No variables in the denominator x y
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Use a T-Chart and graph. y = 2x - 3 xy -2 -1 0 1 2 2(-2) - 3 = -7 2(-1) – 3 = -5 2(0) – 3 = -3 2(1) – 3 = -1 2(2) – 3 = 1 x y Ordered Pair (-2,-7) (-1,-5) (0,-3) (1,-1) (2,1)
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y = 2x - 3 x y Use a T-Chart and graph. xy -2 0 1 2 2(-2) - 3= -7 2(-1) – 3 = -5 (-2,-7) (-1,-5) (0,-3) (1,-1) (2,1) 2(0) – 3 = -3 2(1) – 3 = -1 2(2) – 3 = 1
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y = 2x - 3 x y Use a T-Chart and graph. This is called the “y-intercept” Do you know why? xy -2 0 1 2 2(-2) - 3= -7 2(-1) – 3 = -5 (-2,-7) (-1,-5) (0,-3) (1,-1) (2,1) 2(0) – 3 = -3 2(1) – 3 = -1 2(2) – 3 = 1
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y = 2x - 3 x y Use a T-Chart and graph. xy -2 0 1 2 2(-2) - 3= -7 2(-1) – 3 = -5 (-2,-7) (-1,-5) (0,-3) (1,-1) (2,1) 2(0) – 3 = -3 2(1) – 3 = -1 2(2) – 3 = 1
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y = 2x - 3 x y This line represents all real solutions to y = 2x - 3. Use a T-Chart and graph. xy -2 0 1 2 2(-2) - 3= -7 2(-1) – 3 = -5 (-2,-7) (-1,-5) (0,-3) (1,-1) (2,1) 2(0) – 3 = -3 2(1) – 3 = -1 2(2) – 3 = 1
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You try: y = -2x + 1 x y xy -2 0 1 2 -2(-2) + 1= 5 1 -3 -2(-1) + 1 = 3 Ordered Pair (-2, 5) (-1, 3) (0, 1) (1, -1) (2, -3) Which point is the “y-intercept”? (0,1)
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