1. Newton’s Universal Law of Gravity Every object attracts every other object with a force that is directly proportional to the masses of the objects and inversely proportional to the square of the distance between the centers of the objects.

3. G = Universal Gravitational Constant 6.67E-11 Nkg -2 m 2 m 1 = mass 1 (kg) m 2 = mass 2 (kg) r = distance between the centers (m) F 1 = F 2

4. m1m1 m2m2 r 40N As shown in the diagram below, the force acting on two masses separated by a distance d is 40 N. Calculate the force for each of the following changes: The distance between the masses is doubled. Mass 1 is doubled. The distance between the masses is halved and both masses are doubled. The distance is doubled and both the masses are doubled.

5. ForceMass 1Mass 2distance 40 kg70 kg2 m 6.0 x 10^24 kg7.4 x 10^22 kg3.8 x 10^8 m 600 N6.0 x 10^24 kg60 kg 3 x 10^-7 kg200 kg5 m Use Newton’s Universal Law of Gravity to solve for the unknown quantity in each row of the table shown below

6. The mass of the Earth is 6.0E24kg and its radius is 6.4E6 meters. Find the gravitational force on a 60kg man standing on the Earth. What would the gravitational force be on him in the international space station which is orbiting at a height of 430km above the Earth’s surface? What would his mass be?