1. Pre-Algebra Chapter 10a Review

2. Chapter 10a Review 1) Find the perimeter and area of each figure a) b)Rectangle with length 4m and width 0.5m. 1.5 in 8 in 2 in

3. 1) Find the perimeter and area of each figure a) b)Rectangle with length 4m and width 0.5m. Chapter 10a Review Answer Perimeter = 20 in, Area = 12 in 2 1.5 in 8 in 2 in Perimeter = 9 m, Area = 2 m 2

4. Chapter 10a Review 2) Find the perimeter and area of each figure 3 m 8 m 5 m

5. 2) Find the perimeter and area of each figure Chapter 10a Review Answer Perimeter = 21 m, Area = 19.5 m 2 3 m 8 m 5 m

6. Chapter 10a Review 3) What is the shaded area? 8 cm 3 cm 4 cm

7. 3) What is the shaded area? Chapter 10a Review Answer Area = 64 – 7.07 + 16 = 72.94 cm 2 8 cm 3 cm 4 cm

8. Chapter 10a Review 4) Fill in the missing measures. a)A rectangle. A = 16x 2 y 2 l = 2xy w = ______ b)A circle. A = 20 cm 2 r = _____

9. 4) Fill in the missing measures. a)A rectangle. A = 16x 2 y 2 l = 2xy w = ______ b)A circle. A = 20 cm 2 r = _____ Chapter 10a Review Answer 8xy 2.52

10. Chapter 10a Review 5) a)You have 500 bricks. You want to make as big of a garden as you can. Would it be better to lay the bricks as a square or a triangle? b)What would be the best possible shape?

11. 5) a)You have 500 bricks. You want to make as big of a garden as you can. Would it be better to lay the bricks as a square or a triangle? b)What would be the best possible shape? Chapter 10a Review Answer A circle

12. Chapter 10a Review 6) A pig is being kept within a 10 ft by 15 ft pen. The pig has an equal chance of being anywhere within the pen. There is one doorway. What is the probability that the nose of the pig is within 5 ft of the center of the doorway? center of doorway 15 ft 10 ft 5 ft

13. Chapter 10a Review Answer 0.26 or 26% 6) A pig is being kept within a 10 ft by 15 ft pen. The pig has an equal chance of being anywhere within the pen. There is one doorway. What is the probability that the nose of the pig is within 5 ft of the center of the doorway? center of doorway 15 ft 10 ft 5 ft

14. Chapter 10a Review 7)small pizza  8 in. diameter large pizza  14 in. diameter How many small pizzas could fit on a large pizza (in one layer) if broken up?

15. Chapter 10a Review Answer 3.06 pizzas 7)small pizza  8 in. diameter large pizza  14 in. diameter How many small pizzas could fit on a large pizza (in one layer) if broken up? A = 200.96 in 2 A = 615.44 in 2