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Published byLesley Short Modified over 9 years ago
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More on Riemann Sums
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We will go into more detail today on Riemann sums. Ex.1 Using the integralwe will approximate using sums with 4 subintervals.
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Shown is L 4. x 1 3 5 7 9 Δx=2 Draw a number line for the limits of integration and find Δx.
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Shown is L 4. x 1 3 5 7 9 Δx=2 Count off using the counting variable k, starting at 0. k 0 1 2 3 4
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Shown is L 4. x 1 3 5 7 9 Δx=2 Now find f(x k ) for each k. f(x k ) 1.5 1 1.5 3 1.5 5 1.5 7 1.5 7 k 0 1 2 3 4
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Shown is L 4. x 1 3 5 7 9 Δx=2 Now write in summation notation. f(x k ) 1.5 1 1.5 3 1.5 5 1.5 7 1.5 7 k 0 1 2 3 4 or
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It isn’t necessary to write each step once you understand.
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Shown is R 4. x 1 3 5 7 9 Δx=2 f(x k ) 1.5 1 1.5 3 1.5 5 1.5 7 1.5 7 k 0 1 2 3 4 We use the same number line as before.
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Shown is R 4. x 1 3 5 7 9 Δx=2 Now write in summation notation. f(x k ) 1.5 1 1.5 3 1.5 5 1.5 7 1.5 7 k 0 1 2 3 4 or
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Shown is M 4. x 1 3 5 7 9 Δx=2 f(x j ) 1.5 2 1.5 4 1.5 6 1.5 8 k 0 1 2 3 4 j 0 1 2 3 Identify midpoints in x, then go through the same process as before. x 2 4 6 8
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Shown is M 4. f(x j ) 1.5 2 1.5 4 1.5 6 1.5 8 j 0 1 2 3 Write using summation notation. x 2 4 6 8 or
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Compare to the true value of the integral.
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The major point here is to begin to make the transition from the limits of integration in x, and writing in sigma notation. We have to introduce a counting variable, usually symbolized n, k, j, I, etc.
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