1. Copyright © 2009 Pearson Addison-Wesley 5.2-1 5 Trigonometric Identities

2. Copyright © 2009 Pearson Addison-Wesley 5.2-2 5.1 Fundamental Identities 5.2 Verifying Trigonometric Identities 5.3 Sum and Difference Identities for Cosine 5.4 Sum and Difference Identities for Sine and Tangent 5.5Double-Angle Identities 5.6Half-Angle Identities 5 Trigonometric Identities

3. Copyright © 2009 Pearson Addison-Wesley1.1-3 5.2-3 Sum and Difference Identitites for Cosine 5.3 Difference Identity for Cosine ▪ Sum Identity for Cosine ▪ Cofunction Identities ▪ Applying the Sum and Difference Identities

4. Copyright © 2009 Pearson Addison-Wesley 5.2-4 Difference Identity for Cosine Point Q is on the unit circle, so the coordinates of Q are (cos B, sin B). The coordinates of S are (cos A, sin A). The coordinates of R are (cos(A – B), sin (A – B)).

5. Copyright © 2009 Pearson Addison-Wesley 5.2-5 Difference Identity for Cosine Since the central angles SOQ and POR are equal, PR = SQ. Using the distance formula, we have

6. Copyright © 2009 Pearson Addison-Wesley 5.2-6 Difference Identity for Cosine Square both sides and clear parentheses: Rearrange the terms:

7. Copyright © 2009 Pearson Addison-Wesley 5.2-7 Difference Identity for Cosine Subtract 2, then divide by –2:

8. Copyright © 2009 Pearson Addison-Wesley 5.2-8 Sum Identity for Cosine To find a similar expression for cos(A + B) rewrite A + B as A – (–B) and use the identity for cos(A – B). Cosine difference identity Negative angle identities

9. Copyright © 2009 Pearson Addison-Wesley1.1-9 5.2-9 Cosine of a Sum or Difference

10. Copyright © 2009 Pearson Addison-Wesley1.1-10 5.2-10 Example 1(a) FINDING EXACT COSINE FUNCTION VALUES Find the exact value of cos 15 .

11. Copyright © 2009 Pearson Addison-Wesley1.1-11 5.2-11 Example 1(b) FINDING EXACT COSINE FUNCTION VALUES Find the exact value of

12. Copyright © 2009 Pearson Addison-Wesley1.1-12 5.2-12 Example 1(c) FINDING EXACT COSINE FUNCTION VALUES Find the exact value of cos 87  cos 93  – sin 87  sin 93 .

13. Copyright © 2009 Pearson Addison-Wesley1.1-13 5.2-13 Cofunction Identities Similar identities can be obtained for a real number domain by replacing 90  with

14. Copyright © 2009 Pearson Addison-Wesley1.1-14 5.2-14 Example 2 USING COFUNCTION IDENTITIES TO FIND θ Find an angle that satisfies each of the following: (a)cot θ = tan 25° (b)sin θ = cos (–30°)

15. Copyright © 2009 Pearson Addison-Wesley1.1-15 5.2-15 Example 2 USING COFUNCTION IDENTITIES TO FIND θ Find an angle that satisfies each of the following: (c)

16. Copyright © 2009 Pearson Addison-Wesley1.1-16 5.2-16 Note Because trigonometric (circular) functions are periodic, the solutions in Example 2 are not unique. Only one of infinitely many possiblities are given.

17. Copyright © 2009 Pearson Addison-Wesley 5.2-17 Applying the Sum and Difference Identities If one of the angles A or B in the identities for cos(A + B) and cos(A – B) is a quadrantal angle, then the identity allows us to write the expression in terms of a single function of A or B.

18. Copyright © 2009 Pearson Addison-Wesley1.1-18 5.2-18 Example 3 REDUCING cos (A – B) TO A FUNCTION OF A SINGLE VARIABLE Write cos(90° + θ) as a trigonometric function of θ alone.

19. Copyright © 2009 Pearson Addison-Wesley1.1-19 5.2-19 Example 4 FINDING cos (s + t) GIVEN INFORMATION ABOUT s AND t Suppose that and both s and t are in quadrant II. Find cos(s + t). Sketch an angle s in quadrant II such that Since let y = 3 and r = 5. The Pythagorean theorem gives Since s is in quadrant II, x = –4 and

20. Copyright © 2009 Pearson Addison-Wesley1.1-20 5.2-20 Example 4 FINDING cos (s + t) GIVEN INFORMATION ABOUT s AND t (cont.) Sketch an angle t in quadrant II such that Since let x = –12 and r = 5. The Pythagorean theorem gives Since t is in quadrant II, y = 5 and

21. Copyright © 2009 Pearson Addison-Wesley1.1-21 5.2-21 Example 4 FINDING cos (s + t) GIVEN INFORMATION ABOUT s AND t (cont.)

22. Copyright © 2009 Pearson Addison-Wesley1.1-22 5.2-22 Note The values of cos s and sin t could also be found by using the Pythagorean identities.

23. Copyright © 2009 Pearson Addison-Wesley1.1-23 5.2-23 Example 5 APPLYING THE COSINE DIFFERENCE IDENTITY TO VOLTAGE Common household current is called alternating current because the current alternates direction within the wires. The voltage V in a typical 115-volt outlet can be expressed by the function where ω is the angular speed (in radians per second) of the rotating generator at the electrical plant, and t is time measured in seconds.* *(Source: Bell, D., Fundamentals of Electric Circuits, Fourth Edition, Prentice-Hall, 1988.)

24. Copyright © 2009 Pearson Addison-Wesley1.1-24 5.2-24 Example 5 APPLYING THE COSINE DIFFERENCE IDENTITY TO VOLTAGE (continued) (a)It is essential for electric generators to rotate at precisely 60 cycles per second so household appliances and computers will function properly. Determine ω for these electric generators. Each cycle is 2π radians at 60 cycles per second, so the angular speed is ω = 60(2π) = 120π radians per second.

25. Copyright © 2009 Pearson Addison-Wesley1.1-25 5.2-25 Example 5 APPLYING THE COSINE DIFFERENCE IDENTITY TO VOLTAGE (continued) (b)Graph V in the window [0,.05] by [–200, 200].

26. Copyright © 2009 Pearson Addison-Wesley1.1-26 5.2-26 Example 5 APPLYING THE COSINE DIFFERENCE IDENTITY TO VOLTAGE (continued) (c)Determine a value of so that the graph of is the same as the graph of Using the negative-angle identity for cosine and a cofunction identity gives Therefore, if