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Published byMelvyn Marshall Modified over 8 years ago
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Relativistic Mechanics Momentum and energy
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Momentum p = mv Momentum is conserved in all interactions.
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Total Energy E = mc 2 Total energy is conserved in all interactions.
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Rest Energy E = mc 2 If v = 0 then = 1, E = mc 2 Rest energy is mc 2 Kinetic energy is ( –1)mc 2
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Mass is Energy Or, E = K + mc 2 Particle masses often given as energies –More correctly, as rest energy/c 2 Customary unit: eV = electron·Volt –1 elementary charge pushed through 1 V –Just like 1 J = (1 C)(1 V) –e = 1.60×10 –19 C, so 1 eV = 1.60×10 –19 J
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Particle Masses Electron 511 keV/c 2 Proton 983.3 MeV/c 2 Neutron 939.6 MeV/c 2
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Correspondence At small : Momentum mv mv Energy mc 2 = (1– 2 ) –1/2 mc 2 Binomal approximation (1+x) n 1+nx for small x So (1– 2 ) –1/2 1 + (–1/2)(– 2 ) = 1 + 2 /2 mc 2 mc 2 + 1/2 mv 2 Is this true? Let’s check:
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Convenient Formula E 2 = (mc 2 ) 2 + (pc) 2 Derivation: show R side = ( mc 2 ) 2
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A massless photon p = h/ E = hf = hc/ h = 6.626 10 –36 J·s (Planck constant) mc 2 incalculable: = and m = 0 But E 2 = (mc 2 ) 2 + (pc) 2 works: –E 2 = 0 + (hc/ ) 2 = (hf) 2 –E = hf
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