1. 12-6 Surface Area/Volume of Spheres Holt Geometry Warm Up Warm Up Lesson Presentation Lesson Presentation Lesson Quiz Lesson Quiz

2. Warm Up Find each measurement. 1. the radius of circle M if the diameter is 25 cm 2. the circumference of circle X if the radius is 42.5 in. 3. the area of circle T if the diameter is 26 ft 4. the circumference of circle N if the area is 625 cm 2 12.5 cm 85 in. 169 ft 2 50 cm 12.6 Surface Area/Volume of Spheres

3. Learn and apply the formula for the volume of a sphere. Learn and apply the formula for the surface area of a sphere. Objectives 12.6 Surface Area/Volume of Spheres

4. sphere center of a sphere radius of a sphere hemisphere great circle Vocabulary 12.6 Surface Area/Volume of Spheres

5. A sphere is the locus of points in space that are a fixed distance from a given point called the center of a sphere. A radius of a sphere connects the center of the sphere to any point on the sphere. A hemisphere is half of a sphere. A great circle divides a sphere into two hemispheres 12.6 Surface Area/Volume of Spheres

6. The figure shows a hemisphere and a cylinder with a cone removed from its interior. The cross sections have the same area at every level, so the volumes are equal by Cavalieri’s Principle. You will prove that the cross sections have equal areas in Exercise 39. The height of the hemisphere is equal to the radius. 12.6 Surface Area/Volume of Spheres

7. V(hemisphere) = V(cylinder) – V(cone) The volume of a sphere with radius r is twice the volume of the hemisphere, or. 12.6 Surface Area/Volume of Spheres

9. Example 1A: Finding Volumes of Spheres Find the volume of the sphere. Give your answer in terms of . = 2304 in 3 Simplify. Volume of a sphere. 12.6 Surface Area/Volume of Spheres

10. Example 1B: Finding Volumes of Spheres Find the diameter of a sphere with volume 36,000 cm 3. Substitute 36,000  for V. 27,000 = r 3 r = 30 d = 60 cm d = 2r Take the cube root of both sides. Volume of a sphere. 12.6 Surface Area/Volume of Spheres

11. Example 1C: Finding Volumes of Spheres Find the volume of the hemisphere. Volume of a hemisphere Substitute 15 for r. = 2250 m 3 Simplify. 12.6 Surface Area/Volume of Spheres

12. Check It Out! Example 1 Find the radius of a sphere with volume 2304 ft 3. Volume of a sphere Substitute for V. r = 12 ftSimplify. 12.6 Surface Area/Volume of Spheres

13. Example 2: Sports Application A sporting goods store sells exercise balls in two sizes, standard (22-in. diameter) and jumbo (34- in. diameter). How many times as great is the volume of a jumbo ball as the volume of a standard ball? standard ball: jumbo ball: A jumbo ball is about 3.7 times as great in volume as a standard ball. 12.6 Surface Area/Volume of Spheres

14. Check It Out! Example 2 A hummingbird eyeball has a diameter of approximately 0.6 cm. How many times as great is the volume of a human eyeball as the volume of a hummingbird eyeball? hummingbird: human: The human eyeball is about 72.3 times as great in volume as a hummingbird eyeball. 12.6 Surface Area/Volume of Spheres

15. In the figure, the vertex of the pyramid is at the center of the sphere. The height of the pyramid is approximately the radius r of the sphere. Suppose the entire sphere is filled with n pyramids that each have base area B and height r. 12.6 Surface Area/Volume of Spheres

16. 4r 2 ≈ nB If the pyramids fill the sphere, the total area of the bases is approximately equal to the surface area of the sphere S, so 4r 2 ≈ S. As the number of pyramids increases, the approximation gets closer to the actual surface area. 12.6 Surface Area/Volume of Spheres

18. Example 3A: Finding Surface Area of Spheres Find the surface area of a sphere with diameter 76 cm. Give your answers in terms of . S = 4r 2 S = 4(38) 2 = 5776 cm 2 Surface area of a sphere 12.6 Surface Area/Volume of Spheres

19. Example 3B: Finding Surface Area of Spheres Find the volume of a sphere with surface area 324 in 2. Give your answers in terms of . Substitute 324 for S. 324 = 4r 2 r = 9Solve for r. Substitute 9 for r. The volume of the sphere is 972 in 2. S = 4r 2 Surface area of a sphere 12.6 Surface Area/Volume of Spheres

20. Example 3C: Finding Surface Area of Spheres Find the surface area of a sphere with a great circle that has an area of 49 mi 2. Substitute 49  for A. 49 = r 2 r = 7 Solve for r. S = 4r 2 = 4(7) 2 = 196 mi 2 Substitute 7 for r. A = r 2 Area of a circle 12.6 Surface Area/Volume of Spheres

21. Check It Out! Example 3 Find the surface area of the sphere. Substitute 25 for r. S = 2500 cm 2 S = 4r 2 S = 4(25) 2 Surface area of a sphere 12.6 Surface Area/Volume of Spheres

22. Example 4: Exploring Effects of Changing Dimensions The radius of the sphere is multiplied by. Describe the effect on the volume. original dimensions: radius multiplied by : Notice that. If the radius is multiplied by, the volume is multiplied by, or. 12.6 Surface Area/Volume of Spheres

23. Check It Out! Example 4 The radius of the sphere is divided by 3. Describe the effect on the surface area. original dimensions:dimensions divided by 3: The surface area is divided by 9. S = 4r 2 = 4(3) 2 = 36 m 3 S = 4r 2 = 4(1) 2 = 4 m 3 12.6 Surface Area/Volume of Spheres

24. Example 5: Finding Surface Areas and Volumes of Composite Figures Find the surface area and volume of the composite figure. Give your answer in terms of . Step 1 Find the surface area of the composite figure. The surface area of the composite figure is the sum of the curved surface area of the hemisphere, the lateral area of the cylinder, and the base area of the cylinder. 12.6 Surface Area/Volume of Spheres

25. Example 5 Continued The surface area of the composite figure is L(cylinder) = 2rh = 2(6)(9) = 108 in 2 B(cylinder) = r 2 = (6) 2 = 36 in 2 72 + 108 + 36 = 216 in 2. Find the surface area and volume of the composite figure. Give your answer in terms of . 12.6 Surface Area/Volume of Spheres

26. Step 2 Find the volume of the composite figure. Example 5 Continued Find the surface area and volume of the composite figure. Give your answer in terms of . The volume of the composite figure is the sum of the volume of the hemisphere and the volume of the cylinder. The volume of the composite figure is 144 + 324 = 468 in 3. 12.6 Surface Area/Volume of Spheres

27. Check It Out! Example 5 Find the surface area and volume of the composite figure. Step 1 Find the surface area of the composite figure. The surface area of the composite figure is the sum of the curved surface area of the hemisphere, the lateral area of the cylinder, and the base area of the cylinder. 12.6 Surface Area/Volume of Spheres

28. Check It Out! Example 5 Continued The surface area of the composite figure is Find the surface area and volume of the composite figure. L(cylinder) = 2rh = 2(3)(5) = 30 ft 2 B(cylinder) = r 2 = (3) 2 = 9 ft 2 18 + 30 + 9 = 57 ft 2. 12.6 Surface Area/Volume of Spheres

29. Step 2 Find the volume of the composite figure. Find the surface area and volume of the composite figure. Check It Out! Example 5 Continued The volume of the composite figure is the volume of the cylinder minus the volume of the hemisphere. V = 45 – 18 = 27 ft 3 12.6 Surface Area/Volume of Spheres

30. Lesson Quiz: Part I Find each measurement. Give your answers in terms of . 1. the volume and surface area of the sphere 2. the volume and surface area of a sphere with great circle area 36 in 2 3. the volume and surface area of the hemisphere V = 36 cm 3 ; S = 36 cm 2 V = 288 in 3 ; S = 144 in 2 V = 23,958 ft 3 ; S = 3267 ft 2 12.6 Surface Area/Volume of Spheres

31. Lesson Quiz: Part II 4. A sphere has radius 4. If the radius is multiplied by 5, describe what happens to the surface area. 5. Find the volume and surface area of the composite figure. Give your answer in terms of . The surface area is multiplied by 25. V = 522 ft 3 ; S = 267 ft 2 12.6 Surface Area/Volume of Spheres

32. 12.5 Surface Area/Volume of Spheres Videos: https://ru.khanacademy.org/math/cc-eighth- grade-math/cc-8th-geometry/cc-8th- volume/v/volume-of-a-sphere