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STOICHIOMETRY. The Problem  If 41.6 g of N 2 O 4 reacts with 20.8 g of N 2 H 4 the products will be nitrogen and water. What mass of water will be produced?

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Presentation on theme: "STOICHIOMETRY. The Problem  If 41.6 g of N 2 O 4 reacts with 20.8 g of N 2 H 4 the products will be nitrogen and water. What mass of water will be produced?"— Presentation transcript:

1 STOICHIOMETRY

2 The Problem  If 41.6 g of N 2 O 4 reacts with 20.8 g of N 2 H 4 the products will be nitrogen and water. What mass of water will be produced? Balance equation Mol of N to g G of NH to mol of NO What is the first step?

3 BACK TO QUESTION

4 CORRECT  Setup and balance the equation: N 2 O 4 +N 2 H 4  N 2 +H 2 O

5

6 If 41.6 g of N 2 O 4 reacts with 20.8 g of N 2 H 4 the products will be nitrogen and water. What mass of water will be produced? Mol of N 2 H 4 to grams Mol of N 2 H 4 to mol of H 2 O Grams of N 2 H 4 to mol of H 2 O Next step?

7 TRY AGAIN

8 if 41.6 g of N 2 O 4 reacts with 20.8 g of N 2 H 4 the products will be nitrogen and water. What mass of water will be produced? 20.8g N 2 H 4 X 1 mol N 2 H 4 32.06g N 2 H 4 Next step? Moles of H 2 O to Moles of N 2 H 4 Moles of H 2 O to grams Grams of N 2 H 4 to moles of H 2 O

9 TRY AGAIN

10 If 41.6 g of N 2 O 4 reacts with 20.8 g of N 2 H 4 the products will be nitrogen and water. What mass of water will be produced? 20.8g N 2 H 4 X 1 mol N 2 H 4 X 4 mol H 2 0 32.06g N 2 H 4 2 mol N 2 H 4 Next Step? Grams of H 2 O over Moles Grams of H 2 O over moles of H 2 O Moles of H 2 0 over grams of N 2 H 4

11 Wrong TRY AGAIN

12 if 41.6 g of N 2 O 4 reacts with 20.8 g of N 2 H 4 the products will be nitrogen and water. What mass of water will be produced? 20.8g N 2 H 4 X 1 mol N 2 H 4 X 4 mol H 2 0 X 18.02g H 2 O 32.06g N 2 H 4 2 mol N 2 H 4 1 mol H 2 0 What next? 54.56g of H 2 O 41.89g of H 2 O 35.07g of H 2 O

13 TRY AGAIN

14 If 41.6 g of N 2 O 4 reacts with 20.8 g of N 2 H 4 the products will be nitrogen and water. What mass of water will be produced? COrRecto!!!!!!!!!! 20.8g N 2 H 4 X 1 mol N 2 H 4 X 4 mol H 2 0 X 18.02g H 2 O = 35.073 g H 2 O 32.06g N 2 H 4 2 mol N 2 H 4 1 mol H 2 0 END it HERE


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