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Published byChristina Oliver Modified over 9 years ago
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Circles: Special Angles and Special Segments
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Vertex ON a Circle Secant and Tangent Two Secants
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Vertex Inside a Circle Two Secants
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Vertex Outside a Circle Two Tangents Two Secants Secant & Tangent
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Vertex ON a Circle < measure Find the missing measure 110 35 xx yy
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Vertex ON a Circle < measure Angle = ½ arc 110 35 55 70
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Vertex Inside a Circle < measure Find the missing measure 90 xx 30
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Vertex Inside a Circle < measure Angle =big + small 90 60 30 2
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Vertex Inside a Circle < measure Find the missing measure 160 yy 72
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Vertex Inside a Circle < measure Find supplement first. 160 yy 72 116
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Vertex Inside a Circle < measure Then subtract from 180 160 64 72 116
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Find the missing measure Vertex Outside a Circle < measure xx 216 120 yy 22.5 15 zz 10 50
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Angle =big - small Vertex Outside a Circle < measure 48 216 120 30 22.5 15 60 10 50 2
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Special segments C X A B
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Tangent Segment XA C X A B
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Secant Segment XB C X A B
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External Secant Segment XC C X A B
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Chord CB C X A B
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Tangents Given XA and XB are tangents, what can you conclude about the following diagram? X A B P
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Tangents Given XA and XB are tangents, what can you conclude about the following diagram? X A B P XA XB? Prove it!
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Tangents What do you do to prove something? X A B P Make s
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Tangents What do you know about PA & PB? X A B P
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Tangents What do you know about PA & PB? X A B P PA PB All radii of a circle are
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Tangents What do you know about PX? X A B P
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Tangents What do you know about PX? X A B P PX PX Reflexive
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Tangents What do you know about the s? X A B P
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Tangents What do you know about the s? X A B P They are right s Radius | tangents
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Tangents What else do you know about the s? X A B P
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Tangents What do you know about the s? X A B P s HL Thm
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Tangents What do you know about XA & XB? X A B P
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Tangents What do you know about XA & XB? X A B P XA XB CPCTC
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Secants AX CX = BX DX X A B P C D
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Secants AX CX = BX DX X A B P Why does this work? C D
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Secants AA similarity X A B P Angles intercept the same arc. C D O Therefore the s are proportional.
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Secant & Tangent AX CX = (BX) 2 X A B P C
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Chords AX XC = BX XD X A C D B
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