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Section 2.2 Structure of Geometry. Definitions  Postulate(axiom)- is a statement accepted without proof  Theorem-is a statement that is proven by using.

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Presentation on theme: "Section 2.2 Structure of Geometry. Definitions  Postulate(axiom)- is a statement accepted without proof  Theorem-is a statement that is proven by using."— Presentation transcript:

1 Section 2.2 Structure of Geometry

2 Definitions  Postulate(axiom)- is a statement accepted without proof  Theorem-is a statement that is proven by using defs, postulates, or previously proven theorems

3 Postulates:  Ruler Postulate- the pts on a # line can be paired 1:1 with the set of reals #’s(coords) and the distance between any 2 pts = │ diff of their coords │ Ex: A B -6 4 d AB= │ -6 – 4 │ = 10 units

4 Example :  Find the distance from A to B: A B 3 8 AB = │ 8 – 3 │ = 5

5  Segment Addition Postulate- Pts A, B, & C are collinear and B is in between A & C, then AB + BC = AC ( 2parts sum= whole) If B is between A and C, then AB + BC = AC A B C

6 S is between T and V. R is between S and T. T is between R and Q. QV = 18, QT= 6, TR=RS=SV. Make a sketch and answer.  Find 1. RS2. QS 3. TS4. TV

7 Suppose J is between H and K. Use the segment Addition Postulate to solve for x. Then find the length of each segment. 1. HJ = 2x + 42. HJ = 5x -3 JK = 3x + 3JK = 8x - 9 KH = 22KH = 131 3. HJ = 2x + 1/3 JK = 5x + 2/3 KH = 12x - 4

8  Protractor Postulate- the rays of a given angle can be paired 1:1 on the protractor and the measure is determined by: │ diffs of those real #’s │

9  Angle addition Postulate- If C is in the interior of <AOD, then m<AOC + m<COD = m<AOD.

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11  Q is in the interior of <ROS. S is in the interior of <QOP. P is in the interior of <SOT. S is in the interior of <ROT and m<ROT= 160°. M<SOT = 100° and m<ROQ = m<QOS = m<POT. Make a sketch and answer the following: 1. find m<QOP 2. m<QOT3. m<ROQ

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13 Let Q be in the interior of <POR. Use the angle addition Postulate to solve for x. Find the measure of each angle. 1. m<POQ = (X + 4)° 2. m<POQ = (3x + 7)° m<QOR = (2x – 2)° m<QOR = (5x – 2)° m<POR = 26° m<POR = 61°


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