1. Descriptive Inorganic Chemistry Chem 241 9-10 M, W, F Bill Vining 61 Bacon Hall 436-2698 viningwj@oneonta.edu

2. Inorganic Chemistry One of the three descriptive chemistries: – Organic Chemistry – Biochemistry – Inorganic Chemistry  Theoretical and Practical Chemistries:  Physical Chemistry  Analytical Chemistry

3. Inorganic Chemistry: Chemistry for the rest of the elements.

4. Inorganic Chemistry Transition metal chemistry: – Metal-ligand complexes  Main group and metal-based materials science

5. Descriptive Inorganic Chemistry Chapter 2: Figure 2.2 © 2009 W.H. Freeman

6. First Assignment: Find the best periodic table website. Bring URL and list of why you think it is the best (and any drawbacks). Hand in paper at start of class Friday.

7. Official Stuff Course Website: http://employees.oneonta.edu/viningwj/chem241/http://employees.oneonta.edu/viningwj/chem241/ Syllabus

8. First Topic Where do all these elements come from? How are they made? Are they made?

9. Descriptive Inorganic Chemistry Chapter 2: Figure 2.6 © 2009 W.H. Freeman

10. What aspects of this should we explain?

11. What will our explanations depend on? Thermodynamics: relative stability Kinetics: rate and mechanism

12. General Decrease in Abundance with Atomic Number

13. Even > Odd

14. Peak at Fe

15. Peak at Pb

16. Trough at Be

17. Missing Tc and Pm and Above N = 83

18. Nuclear equations

20. Nucleosynthesis of the Elements Hydrogen Burning 1 H + 1 H  2 H + e + + v e­ 2 H + 1 H  3 He +  3 He + 3 He  4 He +2 1 H Why does this happen only in stars? 4 1 H  4 He + 2e + + 2v e

21. Helium Burning 4 He + 4 He  8 Be 8 Be + 4 He  12 C*  12 C +  3 4 He  12 C +  Is this easier or harder than hydrogen burning?

22. Carbon Burning, etc. 12 C + 4 He  16 O +  16 O + 4 He  20 Ne +  20 Ne + 4 He  24 Mg +  12 C + 12 C  24 Mg +  12 C + 12 C  23 Na + 1 H 12 C + 12 C  20 Ne + 4 He Go back to initial Questions. Can we answer any?

23. The  -Process 20 Ne +   16 O + 4 He 20 Ne + 4 He  24 Mg +  2 20 Ne  16 O + 24 Mg +  40 Ca + 4 He  44 Ti* +  44 Ti* + e -  44 Sc* + v + 44 Sc*  44 Ca +  + + v + 44 Ca + 4 He  48 Ti + 

24. Neutron Capture-Beta Decay