Presentation is loading. Please wait.

Presentation is loading. Please wait.

2Na(s) + Cl 2 (g)  2NaCl (s) Synthesizing an Ionic Compound.

Similar presentations


Presentation on theme: "2Na(s) + Cl 2 (g)  2NaCl (s) Synthesizing an Ionic Compound."— Presentation transcript:

1 2Na(s) + Cl 2 (g)  2NaCl (s) Synthesizing an Ionic Compound

2

3 Explaining Salt Formation using the Born-Haber Cycle

4 Na(s) +  Cl 2  NaCl  H° f = -411 kJ/mol Na(s)  Na(g)  H° f = 108 kJ/mol  Cl 2  Cl(g)  H° f = 122 kJ/mol Na(g)  Na + (g) + e - I 1 = 496 kJ/mol Cl(g) + e -  Cl - (g) E = -349 kJ/mol  H = [  H° f (NaCl)] - [  H° f (Na + ) +  H° f (Cl - ) + I 1 + E]  H = -788 kJ/mol Explaining Salt Formation using the Born-Haber Cycle

5 Describing Electrostatic Attraction and Repulsion E = k Q1Q2Q1Q2 d E > 0 if the charges Q 1 and Q 2 have the same sign Potential energy increases because the particles are repelling E < 0 if the charges Q 1 and Q 2 have different signs Potential energy decreases because the particles are attracting

6 The lattice energy of NaCl is the result of all the electrostatic repulsions and attractions. Because the attractions outweigh the repulsions, the lattice energy is positive and large E = k Q1Q2Q1Q2 d

7

8 Sizes of Ions size depends upon nuclear charge size depends upon numbers of electrons size depends upon orbitals in which the outer electrons reside

9 Within an Isoelectric Series, the higher the atomic number the smaller the ion

10 Covalent Bonds are formed by shared pairs of electrons H H + HH   HH Cl +   Single Bonds Double Bonds O O + C +  O O C O O C  Triple Bonds N N +  N N

11 Resonance Forms O O O  O O O

12 Molecules with an odd number of electrons Molecules in which an atom has less than an octet NO contains 5 + 6 = 11 electrons. No octet can be established Though rare, these are most often encountered in compounds of Born and Beryllium B F F F Exceptions to the Octet Rules

13 Molecules in which an atom has more than an octet This is observed in compounds constructed from period 3 elements and beyond P Cl 3s 3p3d Exceptions to the Octet Rules

14 Strengths of Covalent Bonds Bond dissociation Energy (Bond Energy): is the enthalpy change (  H) required to break a particular bond in a mole of gaseous substance (g)  Cl 2 (g)  H = 242 kJ Bond Energies and the Enthalpy of Reactions  H =  (bond energies of bonds broken) -  (bond energies of bonds formed)

15 Cl 2(g) + H-CH 3  H-Cl(g) + CH 3 Cl  H = [(Cl-Cl) + 4(H-C)] - [(Cl-Cl) + 3(H-C) + (Cl-C)]  H = [242 kJ+4(413 kJ)]-[431 kJ + 4(413kJ) + (328)] = -104 kJ

16 Bond Strength and Bond Length

17 Electronegativity and Bond Polarity “the ability of an atom in a molecule to attract electrons to itself”

18 Electronegativity and Bond Polarity H 2 : E diff = 2.1 -2.1 = 0 HCl: E diff = 3.0 -2.1 = 0.9 Cl 2 : E diff = 3.0 - 3.0 = 0 note that LiF is ionic : E diff = 4.0 - 1.0 = 3.0 H Cl H ++ -- BH 3 2.1-2.0 =.1

19 Ionic Character 4 The bigger the electronegativity difference the more ionic character. 4 1.4 has more ionic character than 1.2

20 noble gas configurations 4 Cl 1- 4 Na 1+ 4 Cu 1+ 4 Sn 2+

21 Isoelectronic 4 O 2-, Cl 1-, Ne, Na 1+, Mg 2+ 4 size trend

22 energy diagram page 366


Download ppt "2Na(s) + Cl 2 (g)  2NaCl (s) Synthesizing an Ionic Compound."

Similar presentations


Ads by Google