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Published byPierce McKenzie Modified over 8 years ago
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EXAMPLE 5 Use a scale factor In the diagram, ∆ TPR ~ ∆ XPZ. Find the length of the altitude PS. SOLUTION First, find the scale factor of ∆ TPR to ∆ XPZ. TR XZ 6 + 6 = 8 + 8 = 12 16 = 3 4
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EXAMPLE 5 Use a scale factor Because the ratio of the lengths of the altitudes in similar triangles is equal to the scale factor, you can write the following proportion. The length of the altitude PS is 15. Write proportion. Substitute 20 for PY. Multiply each side by 20 and simplify. PS PY 3 4 = PS 20 3 4 = = PS 15 ANSWER
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GUIDED PRACTICE for Example 5 In the diagram, ABCDE ~ FGHJK. In the diagram, ∆JKL ~ ∆ EFG. Find the length of the median KM. 7.
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GUIDED PRACTICE for Example 5 JL EG First find the scale factor of ∆ JKL to ∆ EFG. SOLUTION 48 + 48 = 40 + 40 = 96 80 = 6 5 Because the ratio of the lengths of the median in similar triangles is equal to the scale factor, you can write the following proportion.
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GUIDED PRACTICE for Example 5 SOLUTION KM = 42 KM HF = 6 5 KM 35 = 6 5 Write proportion. Substitute 35 for HF. Multiply each side by 35 and simplify.
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