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PERIMETER OF IRREGULAR FIGURES 2/26/16. WARM-UP FIND THE PERIMETER OF THE SQUARE 1 ¼ inches 1 ¼ + 1 ¼ + 1 ¼ + 1 ¼ = 5 inches or 4(1 ¼ ) = 5.

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Presentation on theme: "PERIMETER OF IRREGULAR FIGURES 2/26/16. WARM-UP FIND THE PERIMETER OF THE SQUARE 1 ¼ inches 1 ¼ + 1 ¼ + 1 ¼ + 1 ¼ = 5 inches or 4(1 ¼ ) = 5."— Presentation transcript:

1 PERIMETER OF IRREGULAR FIGURES 2/26/16

2 WARM-UP FIND THE PERIMETER OF THE SQUARE 1 ¼ inches 1 ¼ + 1 ¼ + 1 ¼ + 1 ¼ = 5 inches or 4(1 ¼ ) = 5

3 THE WIDTH OF A RECTANGLE IS 12 CM. WHAT IS THE PERIMETER OF THE RECTANGLE IF THE LENGTH IS 3 TIMES THE WIDTH? 12 cm 3w3w Step 1: Find the length Substitute w for 12 Length = 3w Length = 3 x 12 Length = 36 centimeters Step 2: Find the Perimeter 2(3w) + 2(12)= 2 (3 *12) + 2 (12) = 2( 36) + 2 ( 12) = 72 + 24= 96 centimeters

4 FIND THE PERIMETER OF THIS IRREGULAR FIGURE 11 cm 6 cm 8 cm 13 cm Missing measurement? Missing Measurement: 3 cm Missing Measurement: 7 cm Perimeter: 11+ 6 + 3 + 7+ 8+ 13 = 48 cm

5 PERIMETER OF IRREGULAR FIGURES 46 mm 28.25 mm 7.35 mm 22 mm Missing Measurement: 24 mm Missing Measurement: 35.60 22.00 7.35 24.00 28.25 46.00 + 35.60 163.20 mm = Perimeter

6 FIND THE PERIMETER OF THE FIGURE BELOW: 3 cm 5.5 cm 17 cm 3 cm 6 cm Missing Side: 17 – 5.5 – 5.5 = 6 cm Find the Perimeter: 17 + 3 + 5.5 + 6 + 6 + 6 + 5.5 + 3 = 52 cm

7 Mr. Bill’s backyard is in the shape of a rectangle. It took him 678 feet of fence to enclose his back yard. If the length of the yard is twice as long as the width, the width being 113 feet long. What is the length of Mr. Bill’s yard?

8 WHAT IS THE LENGTH OF SIDE X, IF THE PERIMETER IS 900 MILLIMETERS? 135 mm 211 mm X 135 + 135 + 211 + 211 + X = 900 mm 692 + X = 900 mm - 692 -692 X = 208 mm


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