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Published byRafe Foster Modified over 9 years ago
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When electric charges flow they experience opposition or resistance which reduces the amount of energy they have Greater resistance -> greater amount of energy each charge has to give up
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Filament – high resistance Therefore, lot’s of energy taken from each electron and turned into light Wire – low resistance Therefore, little energy lost – turned mainly into heat
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The amount of energy (voltage) required to push electrons (current) through a conductor
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German Physicist Georg Ohm determined that for a given conductor, the ratio of voltage to current (V/I) is constant We call this constant resistance (Measured in Ohms - ) = ConstantResistance
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Relates voltage, current and resistance Note: E stands for electric potential (commonly known as voltage)
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Electrical Insultator ◦ Prevents the transfer of electric charges ◦ Ex: Air, glass, rubber, paper Electrical conductor ◦ Low resistance which allows electric charges to flow easily ◦ Ex: copper
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A single cell is set-up in a circuit with a switch and a resistor. For the resistor, a voltmeter is set-up and it measures 1.3V and an ammeter is set-up and it measures 3.5A. a) Draw the circuit with the correct set- up of a voltmeter and ammeter b) Calculate the resistance of the resistor
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If a resistor has a resistance of 1000 and the current is 2.0A. What will be the voltage drop across the resistor?
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Pg 330 # 1a Pg 332 # 1, 3-5 Pg 331 # 5ab,7,8
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Series ◦ Only one path for current to flow
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Parallel ◦ More than one path for current to take
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We have four tools we can use to analyze circuits: ◦ Kirchoff’s Current Law (KCL) ◦ Kirchoff’s Voltage Law (KVL) ◦ Ohm’s Law ◦ Equivalent Resistance (Series and Parallel)
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At any junction (Point) in the circuit, the current going in equals the current going out At a point, I in = I out Note: In any series circuit, every point has the same current
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In any complete path in a circuit, the sum of voltage rises (sources) is equal to the sum of voltage drops (loads) For a path, V rises = V drops
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Pg 337 # 1-3 Pg 343 # 1, 2, 4
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If you have many resistors (or loads) in a circuit, finding the equivalent resistance allows you to replace multiple resistors with a single resistor This allows easier analysis of circuits
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The easiest way to put this formula into a calculator is to use your inverse button (x -1 )
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Pg 339 # 4-6 Pg 340 # 7
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