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What do we (not) know about Nodes and where do we go from here ? Dario Bressanini - Georgetown University, Washington, D.C. and Universita’ dell’Insubria, ITALY Peter J. Reynolds - Georgetown University, Washington, D.C. and Office of Naval Research PacifiChem 2000 - Honolulu, HI
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Nodes and the Sign Problem So far, solutions to sign problem not proven to be efficient Fixed-node approach is efficient. If only we could have the exact nodes … … or at least a systematic way to improve the nodes... … we could bypass the sign problem
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The Plan of Attack Study the nodes of exact and good approximate trial wave functions Understand their properties Find a way to parametrize the nodes using simple functions Optimize the nodes minimizing the Fixed-Node energy
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The Helium Triplet First 3 S state of He is one of very few systems where we know exact node For S states we can write For the Pauli Principle Which means that the node is
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The Helium Triplet Independent of r 12 Independent of Z: He, Li +, Be 2+,... have the same node Present in all 3 S states of two-electron atoms The node is more symmetric than the wave function itself The wave function is not factorizable but r1r1 r2r2 r 12 r1r1 r2r2
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The Helium Triplet Implies that for 2 3 S helium NOT This is NOT trivial N is the Nodal Function N = r 1 -r 2, Antisymmetric f = unknown, totally symmetric The exponential is there to emphasize the positivity of the non-nodal factor The HF function has the exact node
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Nodal Conjectures Which of these properties are present in other systems/states ? Some years ago J. B. Anderson found some of these properties in 1 P He and u H 2 Could these be general properties of the nodal surfaces ? For a generic system, what can we say about N ?
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Helium Singlet 2 1 S It is a 1 S ( 1 s 2 s ) so we write Plot the nodes (superimposed) for different using an Hylleraas expansion (125 terms) Plot r1r1 r2r2 r
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Helium Singlet 2 1 S I.e., although, the node does not depend on (or does very weakly) r1r1 r2r2 A very good approximation of the node is Surface contour plot of the node The second triplet has similar properties
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Lithium Atom Ground State The RHF node is r 1 = r 3 if two like-spin electrons are at the same distance from the nucleus then =0 This is the same node we found in the He 3 S How good is the RHF node? RHF is not very good, however its node is surprisingly good ( might it be the exact one? ) DMC( RHF ) = -7.47803(5) a.u. Arne & Anderson JCP 1996 Exact = -7.47806032 a.u. Drake, Hylleraas expansion
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The Node of the Lithium Atom Note that RHF belongs to a higher symmetry group than the exact wave function. The node has even higher symmetry, since it doesn’t depend on r 2 or r ij  is the anti-symmetrizer, f, g and h are radial functions, and J is a totally symmetric function (like a Jastrow) CI-GVB has exactly the same node, I.e., r 1 = r 3
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Li Atom: Exact Wave Function The exact wave function, to be a pure 2 S, must satisfy This expression is not required to vanish for r 1 = r 3
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To study an “almost exact” node we take a Hylleraas expansion for Li with 250 terms Energy Hy = -7.478059 a.u. Exact = -7.4780603 a.u. How different is its node from r 1 = r 3 ?? Li atom: Study of Exact Node
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The full node is a 5D object. We can take cuts (I.e., fix r ij ) The node seems to be r 1 = r 3, taking different cuts Do a DMC simulation to check the attempted nodal crossing of the Hy node AND r 1 = r 3 r3r3 r1r1 r2r2 r1r1 r3r3 Crosses both Crosses one
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Li atom: Study of Exact Node 92 attempted crossing of both nodes 6 crossed only Hy but not r 1 = r 3 Results Out of 6*10 6 walker moves: The 6 were either in regions where the node was very close to r 1 = r 3 or an artifact of the linear expansion
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We performed a DMC simulation using a HF guiding function (with the r 1 = r 3 node) and an accurate Hylleraas trial function (to compute the local energy with re-weighting) = 0.001 -7.478061(3) a.u. = 0.003 -7.478062(3) a.u. Exact -7.4780603 a.u. Is r 1 = r 3 the exact node of Lithium ? Li atom: Study of Exact Node
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For Lithium N ( R ) = r 1 - r 3 Strong Conjecture Nodal Structure Conjecture Weak Conjecture
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Beryllium Atom Be 1 s 2 2 s 2 1 S ground state In 1992 Bressanini and others found that HF predicts 4 nodal regions JCP 97, 9200 (1992) The HF node is ( r 1 - r 2 )*( r 3 - r 4 ) and is wrong DMC energy -14.6576(4) Exact energy -14.6673 factors into two determinants each one “describing” a triplet Be +2 Conjecture: exact has TWO nodal regions
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Beryllium Atom Be optimized 2 configuration T Plot cuts of (r 1 -r 2 ) vs (r 3 -r 4 ) In 9-D space, the direct product structure “opens up” Node is (r 1 -r 2 ) x (r 3 -r 4 ) +...
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Beryllium Atom Be optimized 2 configuration T Clues to structure of additional terms? Take cuts... With alpha electrons along any ray from origin, node is when beta 's are on any sphere (almost). Further investigation leads to... Node is (r 1 -r 2 ) x (r 3 -r 4 ) + r 12. r 34 +...
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Beryllium Atom Be optimized 2 configuration T Using symmetry constraints coupled with observation, full node (to linear order in r’ s ) can only contain these two terms and one more: (r 1 -r 2 ) x (- r 13 + r 14 - r 23 + r 24 ) + (r 3 -r 4 ) x (- r 13 - r 14 + r 23 + r 24 )
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Conclusions “Nodes are weird” M. Foulkes. Seattle meeting 1999 “...Maybe not” Bressanini & Reynolds. Honolulu 2000 Exact nodes (at least for atoms) seem to depend on few variables have higher symmetry than itself resemble polynomial functions Possible explanation on why HF nodes are quite good: they “ naturally” have these properties It seems possible to optimize nodes directly
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