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Published byHannah Byrd Modified over 8 years ago
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If N= (P₁) ˣ ×(P₂)ʷ ×(P₃) ʸ Then no. of factors of N=(x+1) ×(w+1) ×(y+1) For example: N = 50² × 14 Find the total factors, prime factors, composite factors, even factors and odd factors of N.
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N = (5²×2)² ×7×2 =5⁴×2³×7 total no. of factors of N= 5 × 4×2 =40 Prime factors = 3 Composite factors = 40-3-1=36 Odd factors = 5 × 2 = 10 Even factors = 40-10= 30
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Q.) N =100 ²×15 Find total no. of factors Find total no. of factors which are multiple of 100 Q.) Find the total number of factors of 576? Q.) If N = 12³×3 ⁴×5², find the total no. of even factors Q.) How many factors of 1 crore would end with zero
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