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Published byTrevor Butler Modified over 8 years ago
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3.6 The Chain Rule Y= f(g(x)) Y’=f’(g(x)) g’(x)
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Chain rule Unlocks many derivatives
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actual computations r=10, A=100 pi cm^2 r= 10.1 A= 102 pi cm^2
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Use the chain rule: Y=sec(6x-3) Y= (6x-3)^7
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3.7 Implicit differentiation Use when the function is not given as y in terms of x,
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Or when one variable cannot be conveniently separated from the other.
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3.8 Linear approximation and differentials For x values close to “x “ the tangent line approximates the function.
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Equation of the tangent line at the point ( c, f (c) ) y= f(c) + f’ (c) (x-c)
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Differentials “ dx” can have a numeric value
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Example How is the area of a circle changing when the radius is increasing at 0.01 cm/sec at the instant the radius is 5 cm ?
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Using differentials to approximate the increase in a circle’s area Radius = 10 cm Radius is increased by 0.1 cm
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Ex. The edges of a cube are increasing at 3 cm/sec. How fast is the volume changing when: a) edge= 1 cm b) edge = 10 cm
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Approximate the cube root of 8.1 using differentials.
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Approximate the square root of 62.
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Volume of a fluid flowing through a pipe at a fixed pressure v=kr^4 How will a 10 % increase in the radius affect the volume?
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Find the differential – dy – using implicit differentiation xy^2 +x^2 y – 4 = 0
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Review problems
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Find the amount of possible error in computing the area Circle Diameter=200 cm Diameter measured with + 0.025 cm
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Find the amount of possible error in computing the area Equilateral triangle Side = 90 m Side measured with + 1 m
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Use differentials to find the cube root of 64.12
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Test on all of chapter 3 Hint Know everything
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