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5.4 – Use Medians and Altitudes
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Median Line from the vertex of a triangle to the midpoint of the opposite side
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In your group, each person draw a different sized triangle. One should be scalene obtuse, one scalene acute, scalene right, and one isosceles. Then construct the medians of the triangle.
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A B C **always inside the triangle
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Point of concurrency Property centroid 2/3 the distance from each vertex and 1/3 distance from the midpoint
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Special Segment Definition Median Line from the vertex to midpoint of opposite side
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Concurrency PropertyDefinition Centroid 2/3 the distance from each vertex and 1/3 distance from the midpoint
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Altitude Line from the vertex of a triangle perpendicular to the opposite side
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In your group, each person draw a different sized triangle. One should be scalene obtuse, one scalene acute, scalene right, and one isosceles. Then construct the altitudes of the triangle.
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AB C
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Point of concurrency Property orthocenter none
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Special SegmentDefinition Altitude Line from vertex to the opposite side
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Concurrency PropertyDefinition orthocenter If obtuse – outside of triangle If right – at vertex of right angle If acute – inside of triangle
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Perpendicular Bisector Circumcenter Angle Bisector Incenter MedianCentroid AltitudeOrthocenter P A M A C I C O
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In PQR, S is the centroid, PQ = RQ, UQ = 5, TR = 3, and SU = 2. Find the measure. Find TP. 3
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In PQR, S is the centroid, PQ = RQ, UQ = 5, TR = 3, and SU = 2. Find the measure. Find SV. 3 2
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In PQR, S is the centroid, PQ = RQ, UQ = 5, TR = 3, and SU = 2. Find the measure. Find RU. 3 2 4 + 2 =6 4
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In PQR, S is the centroid, PQ = RQ, UQ = 5, TR = 3, and SU = 2. Find the measure. Find ST. 3 2 4 3
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In PQR, S is the centroid, PQ = RQ, UQ = 5, TR = 3, and SU = 2. Find the measure. Find VQ. 3 2 4 3 5
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In ABC, G is the centroid, AE = 12, DC = 15. Find the measure. Find GE and AG. A C B F D E G 12 GE = 4 AG = 8
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In ABC, G is the centroid, AE = 12, DC = 15. Find the measure. Find GC and DG. A C B F D E G 12 GC = 10 DG = 5 15
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Point L is the centroid for NOM. Use the given information to find the value of x. OL = 5x – 1 and LQ = 4x – 5 5x – 1 = 2(4x – 5) 5x – 1 = 8x – 10 –1 = 3x – 10 9 = 3x 3 = x 5x – 1 4x – 5
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Point L is the centroid for NOM. Use the given information to find the value of x. LP = 2x + 4 and NP = 9x + 6 3(2x + 4) = 9x + 6 6x + 12 = 9x + 6 12 = 3x + 6 6 = 3x 2 = x 2x + 4 9x + 6
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5.4322-324 WS 3-7, 17-19, 34, 35 Constructing the Centroid and Orthocenter HW Problems #18 Angle bisector
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