1. All Chapter 11 Review Whiteboard work time

2. Make 3 columns, first one heterozygous (He), second one homozygous dominant (HD), third homozygous recessive (HR). Place the following genotypes under the correct heading. TT Bb DD Ff tt dd Dd ff Tt bb BB FF

3. Make 3 columns, first one heterozygous (He), second one homozygous dominant (HD), third homozygous recessive (HR). Place the following genotypes under the correct heading. Heterozygou s Homozygou s Dominant Homozygou s Recessive Dd Tt Bb Ff TT DD BB FF tt dd ff bb

4. Determine the phenotype for each genotype using the information provided for SpongeBob. Yellow body color is dominant to blue. YY _________________ Yy _________________ yy _________________ Square shape is dominant to round. SS _________________ Ss _________________ ss _________________

5. Determine the phenotype for each genotype using the information provided for SpongeBob. Yellow body color is dominant to blue. YY YELLOW Yy YELLOW yy BLUE Square shape is dominant to round. SS SQURE Ss SQUARE ss ROUND

6. For each phenotype, give the genotypes that are possible for Patrick. A tall head (T) is dominant to short (t). Tall = ________________________ Short = __________________________ Pink body color (P) is dominant to yellow (p). Pink body = ___________________ Yellow body = _____________________

7. For each phenotype, give the genotypes that are possible for Patrick. A tall head (T) is dominant to short (t). Tall = TT or Tt Short = tt Pink body color (P) is dominant to yellow (p). Pink body = PP or Pp Yellow body = pp

8. SpongeBob SquarePants recently met SpongeSusie Roundpants at a dance. SpongeBob is heterozygous for his square shape, but SpongeSusie is round. Create a Punnett square to show the possibilities that would result if SpongeBob and SpongeSusie had children. HINT: Remember square (S) is dominant to round (s). 1.Show your Punnett Square work. 2.Write the genotypic ratio.

9. SpongeBob SquarePants recently met SpongeSusie Roundpants at a dance. SpongeBob is heterozygous for his square shape, but SpongeSusie is round. Create a Punnett square to show the possibilities that would result if SpongeBob and SpongeSusie had children. HINT: Remember square (S) is dominant to round (s). 1 Ss: 1 ss (50/50 chance of square or round bodied offspring)

10. Patrick met Patti at the dance. Both of them are heterozygous for their pink body color (P), which is dominant over a yellow body color (p). Create a Punnett square to show the possibilities that would result if Patrick and Patti had children. 1.Show your Punnett Square work. 2.Write the phenotype ratio.

11. Patrick met Patti at the dance. Both of them are heterozygous for their pink body color (P), which is dominant over a yellow body color (p). Create a Punnett square to show the possibilities that would result if Patrick and Patti had children. 3 Pink: 1 Yellow

12. Give all possible gamete combinations for the following: 1. RRYY 2. RrYY 3. RRYy 4. RrYy 5. Rryy

13. Give all possible gamete combinations for the following: 1. RRYY one - RY 2. RrYY two – RY and rY 3. RRYy two – RY and Ry 4. RrYy four – RY, Ry, rY, ry 5. Rryy two – Ry and ry

14. Black (B) hair is dominant over brown in horses. Galloping (G) is dominant over trotting also. A.What are the possible genotypes for a black galloping horse? B. What are the possible genotypes for a black trotting horse? C. What are the possible genotypes for a brown galloping horse?

15. Black (B) hair is dominant over brown in horses. Galloping (G) is dominant over trotting also. A.What are the possible genotypes for a black galloping horse? BBGG, BbGG, BBGg, and BbGg B. What are the possible genotypes for a black trotting horse? BBgg or Bbgg C. What are the possible genotypes for a brown galloping horse? bbGG or bbGg

16. Black (B) hair is dominant over brown in horses. Galloping (G) is dominant over trotting also. Cross a heterozygous black galloping horse with a brown trotting horse. A.Genotypes of parents? B.Possible gametes of the parents? C.Complete the 2-trait Punnett square. D.Phenotypic ratio?

17. Cross a heterozygous black galloping horse with a brown trotting horse. A.Genotypes of parents? BbGg x bbgg B.Possible gametes of the parents? BbGg – 4 – BG, Bg, bG, bg Bbgg – 1 - bg A.Complete the 2-trait Punnett square. B.Phenotypic ratio? 1 black gallop 1 black trot 1 brown gallop 1 brown trot

18. Guinea pigs have four different types of coats. Rough coats (R) are dominant to smooth coats. Short hair (S) is dominant to long hair. Cross two guinea pigs that are heterozygous for both traits. A.Genotypes of parents? B.Possible gametes of the parents? C.Complete the 2-trait Punnett square. D.Phenotypic ratio?

19. A.Genotypes of parents? Both parents are RrSs. A.Possible gametes of the parents? Both parents will have 4 possible gametes – RS, Rs, rS, rs A.Complete the 2-trait Punnett square. B.Phenotypic ratio? 9:3:3:1 – did you have it memorized???